Answer:
22.11 m / s
Explanation:
The falcon catches the prey from behind means both are flying in the same direction ( suppose towards the left )
initial velocity of falcon = 28 cos 35 i - 28 sin 35 j
( falcon was flying in south east direction making 35 degree from the east )
momentum = .9 ( 28 cos 35 i - 28 sin 35 j )
= 20.64 i - 14.45 j
initial velocity of pigeon
= 7 i
initial momentum = .325 x 7i
= 2.275 i
If final velocity of composite mass of falcon and pigeon be V
Applying law of conservation of momentum
( .9 + .325) V = 20.64 i - 14.45 j +2.275 i
V = ( 22.915 i - 14.45 j ) / 1.225
= 18.70 i - 11.8 j
magnitude of V
= √ [ (18.7 )² + ( 11.8 )²]
= 22.11 m / s
The question is incomplete but still I answer to assume your thinking.
The picture is attached below!.
Here,
F is the force with which you pull up the incline.
N is the normal force.
w is the weight acting downward.
Axis are mentioned in the attached picture.
Concept:You can see there is no movement of object in the y-direction that means acceleration is zero in y-direction, sum of all the forces in y-direction equal to zero.
According to newton second law,
<span>∑ F = ma
</span>As, acceleration is zero in y-direction, so right hand side is zero in the above equation.
<span>∑ F = 0</span>
N-wcosθ=0
N= m*g*cos25°
N= m*(9.8)*(0.9063)
N= 8.8817*mBy putting the value of mass(m)(not given in the question) you will get the answer.
Hopefully, this is the answer of your question.
Answer:
A) F=-20.16×10⁹N
B) if the distance doubles, force is 4 times smaller.
Explanation:
q1=-28C
q2=5mC=0.005C
d=25cm=0.25m
Electrostatic force between charges: F=k×q1×q2/d², where k is a coefficient that has the value k=9 × 10⁹ N⋅m²⋅C^(-2) for air.
Thus:
F=9×10⁹×(-28)×0.005/0.25²
F=-20.16×10⁹N
The minus sign indicates attraction.
If distance doubles, d1=2×d, then we have 4d² at the denominator and the force is 4 times smaller.