Answer:
27.95[kW*min]
Explanation:
We must remember that the power can be determined by the product of the current by the voltage.
where:
P = power [W]
V = voltage [volt]
I = amperage [Amp]
Now replacing:
Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]
Answer:
C) No work is required to move the negative charge from point A to point B.
Explanation:
An equipotential surface is defined as a surface connecting all the points at the same potential.
Therefore, when a charge moves along an equipotential surface, it moves between points at same potential.
The work done when moving a charge is given by
where
q is the charge
is the potential difference between the initial and final point of motion of the charge
However, the charge in this problem moves along an equipotential surface: this means that the potential does not change, so
And so, the work done is also zero.
Answer:
Part (i)
Z = 39.06 ohm
Part (ii)
R = 21.7 ohm
Explanation:
a) here we know that
maximum value of EMF = 125 V
maximum value of current = 3.20 A
now by ohm's law we can find the impedence as
now we will have
Part b)
Now we also know that
now we have