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Novay_Z [31]
1 year ago
3

The ta then informs the class that some unknowns may have only contained distilled water so the student wants to make sure their

unknown has a cation in it. Which test will always results in observations that will confirm the presence of a cation?.
Chemistry
1 answer:
Vlad [161]1 year ago
6 0

The students should behavior a boiling test to check on the pattern.to test the purity of your water, pour a bit of water into a disposable.

Transparent cup. upload some drops of Silver solution. If the water turns white and cloudy, it is not naturally sufficient for mirroring.

The perfect take a look at to decide the water is to behavior a boiling point take a look at on it. naturally distilled water boils at exactly one hundred°C. If the sample consists of other ions in solution, then it's going to now not boil at exactly 100°C as anticipated. The presence of impurities will increase the boiling point of water.

While water is distilled, it lacks minerals like calcium, magnesium, and fluoride which are important for maintaining a balanced food regimen. Distilled water, although secure to drink, devoids you of these minerals that could dehydrate you. It isn't always the purest form of water. even as purified water is more perfect and more healthy.

Learn more about Distilled water here:-brainly.com/question/19091247

#SPJ4

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What is POH of a solution containing hydrogen ion concentration of 0.008​
kotykmax [81]

Given-

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3 years ago
The molar heat of fusion of platinum (Pt) is 4.700 kcal/mol. How much heat must be added to 85.5 g of
zvonat [6]

Answer:

2.07 Kcal heat must be added to completely melt the platinum.

Explanation:

Given data:

Molar heat of fusion =  4.700 Kcal / mol

Mass of platinum = 85.5 g

Heat of fusion = ?

Solution:

Formula:

ΔH = n × molar heat of fusion

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Now we will calculate the number of moles:

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3 0
3 years ago
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34.1 mg NaCl in 117.3 mL of solution
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The molarity of the solution will be 4.97 M.

<h3>What is molarity?</h3>

It is the number of moles of solutes per 1 liter of solvent or solution.

Mole of 34.1 g NaCl = 34.1/58.44 = 0.5835 mol

117.3 mL = 117.3/1000 = 0.1173 L

Molarity of the solution = 0.5835/0.1173 = 4.97 M

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6 0
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