They are examples of elements.
        
                    
             
        
        
        
You must burn 1.17 g C to obtain 2.21 L CO₂ at STP.
The balanced chemical equation is
C + O₂ → CO₂.
<em>Step 1</em>. Convert <em>litres of CO₂ to moles of CO₂</em>.
STP is <em>0 °C and 1 bar</em>. At STP the volume of 1 mol of an ideal gas is 22.71 L.
Moles of CO₂ = 2.21 L CO₂ × (1 mol CO₂/22.71 L CO₂) = 0.097 31 mol CO₂
<em>Step 2</em>. Use the molar ratio of C:CO₂ to <em>convert moles of CO₂ to moles of C
</em>
Moles of C = 0.097 31mol CO₂ × (1 mol C/1 mol CO₂) = 0.097 31mol C
<em>Step 3</em>. Use the molar mass of C to <em>calculate the mass of C
</em>
Mass of C = 0.097 31mol C × (12.01 g C/1 mol C) = 1.17 g C
It looks as if you are using the <em>old (pre-1982) definition</em> of STP. That definition gives a value of 1.18 g C.
 
        
                    
             
        
        
        
Answer:
The Lewis structure to this question can be described as follows:
Explanation:
Structure of Lewis for  
:  
The maximum number of electrons from valence in 
  is 8 (6 from S as well as 2 from negative change).  
The valence electrons in the Lewis structure are placed on four sides of the atom.  
Thus the structure of Lewis for 
 is as follows:
![\left[\begin{array}{ccc} &. .&\\: &S&:\\&. .&\end{array}\right] ^{2-}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%26.%20.%26%5C%5C%3A%20%26S%26%3A%5C%5C%26.%20.%26%5Cend%7Barray%7D%5Cright%5D%20%5E%7B2-%7D)
Lewis Mg Structure:  
Complete valence electrons are 2 in Mg.  
The Lewis structure for Mg, therefore, is as follows:

The Lewis structure for  
The maximum valence of electrons  
 in is=  0.
Thus, the structure for  
 is as follows:
  
Lewis structure for P :
The maximum number of valence electrons in P is = 5.
Thus, the structure for P is=

 
        
             
        
        
        
The answer is 7.  
Orbitals are the levels of organization of electrons, the areas where they are most likely to be found. Each orbital holds 2 electrons, and orbitals are held in subshells. 
The subshells are s, p, d, and f. This is organized from smallest subshell to largest. s has 1 orbital, p has 3, d has 5, and f has 7. Thus, your answer is the f subshell contains 7 orbitals.
Hope this helps!