For any planet, if the planet were to shrink, but have constant mass, what would happen to the value of gravity acceleration (g)
1 answer:
The value of the gravity acceleration on the planet's surface increases
Explanation:
The gravitational acceleration on the surface of a planet is given by:
where
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
In this problem, we are told that the planet shrinks, therefore the new radius is smaller than the original radius:
while the mass remains the same:
Therefore, the new acceleration of gravity is
We see that the value of g is inversely proportional to the square of the radius of the planet: therefore, since , it means that
, so when the planet shrinks, the value of the gravity acceleration on the planet's surface increases.
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Answer:
λ = 482.05 nm
Explanation:
The diffraction phenomenon and the diffraction grating is described by the expression
d sin θ = m λ
where d is the distance between two consecutive slits, λ the wavelength and m an integer representing the order of diffraction
in this case they indicate the distance between slits, the angle and the order of diffraction
λ = d sin θ / m
let's calculate
λ = 1.00 10⁻⁶ sin 74.6 / 2
λ = 4.82048 10⁻⁷ m
Let's reduce to nm
λ = 4.82048 10⁻⁷ m (10⁹ nm / 1 m)
λ = 482.05 nm
Let's calculate the average acceleration. It is the rate of changing speeds. Hence, we need to calculate the difference of speeds. 10-6=4 m/s. The rate is now 
.
In general, the formula for the mean acceleration between two times 1 and 2 is given by:
where v1 and v2 are the speeds at the respective points and T is the time interval between them.
In general, the formula for the mean acceleration between two times 1 and 2 is given by: