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Alona [7]
3 years ago
13

Please help me answer these questions ASAP !

Physics
1 answer:
vodomira [7]3 years ago
3 0
1. Layer A is the oldest. The law of superposition says that the oldest layer is at the bottom whilst the newest is at the top.
2. The law of original horizontality.
3. The law of original lateral continuity.
You might be interested in
6. Draw a velocity-time graph for an object originally traveling at -3 m/s. The object
faltersainse [42]

See the graph in attachment

Explanation:

In this problem we have to draw a velocity-time graph for an object travelling initially at -3 m/s, then slowing down and turning around.

In the graph, we see that the initial velocity at time t = 0 is

v_0 = -3 m/s

and it is negative, so below the x-axis.

Later, the object slows down: this means that the magnitude of its velocity increases, therefore (since the velocity is negative) the curve must go upward, approaching and reaching the x-axis (which corresponds to zero velocity).

After that, the object's velocity keep increasing, but now it is positive: this means that the object is travelling in a direction opposite to the initial direction, so it has turned around.

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

4 0
3 years ago
A horizontal uniform bar of mass 2.7 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to t
Jlenok [28]

Answer:

14.36 N

Explanation:

T_{1} = Tension in string 1

T_{2} = Tension in string 2

m_b = mass of the bar = 2.7 kg

W_b = weight of the bar

weight of the bar is given as

W_b = m_{b} g = (2.7) (9.8) = 26.46N

m_m = mass of the bar = 1.35 kg

W_m = weight of the monkey

weight of the monkey is given as

W_m = m_{m} g = (1.35) (9.8) = 13.23N

Using equilibrium of torque about left end

W_{m} (AB) + W_{b} (AB) = T_{2} (AC)\\W_{m} (AB) + W_{b} (AB) = T_{2} (AD - CD)\\(13.23) (1.5) + (26.46)(1.5) = T_{2} (3 - 0.65)\\\\T_{2} = 25.33 N

Using equilibrium of force in vertical direction

T_{1} + T_{2} = W_{b} + W_{m}\\T_{1} + 25.33 = 26.46 + 13.23\\T_{1} = 14.36 N

7 0
3 years ago
How does the particle model indicate positive acceleration and how does it indicate negative acceleration? An example of particl
MrMuchimi

Answer:

Explanation:

The diagram has a fairly simple explanation. In the top diagram, the space between the particle is increasing. That means that acceleration is increasing. The bottom diagram shows just the opposite. The particle starts off making large "distances" between where the particle is recorded and then the distances between recordings lessens and the particle is slowing down.

Rule: the greater the "distance" between dot positions, the greater the acceleration, because the speed is large.

Top diagram: increasing distance between dots = larger speed. The distance becomes greater as the particle moves to the right.

Bottom diagram: starts off large and decreases as we move from left to right  = - acceleration.  

5 0
3 years ago
Alex goes cruising on his dirt bike. He rides 700m north, 300m east, 400 m north, 600m west, 1200m south, 300m east and finally
Bess [88]

Find Displacement and Distance

displacement ...

north is 700+400+100 =1200m n

south=1200m

1200-1200=0


east is 300+300=600m

west is 600m

600-600=0

back at dtart. displ zero


distance is 700+ 300m + 400 m + 600m + 1200m + 300m + 100m  = 3600m


3 0
3 years ago
An ancient club is found that contains 100 g of pure carbon and has an activity of 6.5 decays per second. Determine its age assu
never [62]

Answer:

The age of living tree is 11104 years.

Explanation:

Given that,

Mass of pure carbon = 100 g

Activity of this carbon is = 6.5 decays per second = 6.5 x60 decays/min =390 decays/m

We need to calculate the decay rate

R=\dfrac{-dN}{dt}=\lambda N=\dfrac{0.693}{t_{\frac{1}{2}}}N....(I)

Where, N = number of radio active atoms

t_{\frac{1}{2}}=half life

We need to calculate the number of radio active atoms

For N_{12_{c}}

N_{12_{c}}=\dfrac{N_{A}}{M}

Where, N_{A} =Avogadro number

N_{12_{c}}=\dfrac{6.02\times10^{23}}{12}

N_{12_{c}}=5.02\times10^{22}\ nuclie/g

For N_{c_{14}}

N_{c_{14}}=1.30\times10^{-12}N_{12_{c}}

N_{c_{14}}=1.30\times10^{-12}\times5.02\times10^{22}

N_{c_{14}}=6.526\times10^{10}\ nuclei/g

Put the value in the equation (I)

R=\dfrac{0.693\times6.526\times10^{10}\times60}{5700\times3.16\times10^{7}}

R=15.0650\ decay/min g

100 g carbon will decay with rate

R=100\times15.0650=1507\ decay/min

We need to calculate the total half lives

(\dfrac{1}{2})^{n}=\dfrac{390}{1507}

2^n=\dfrac{1507}{390}

2^n=3.86

n ln 2=ln 3.86

n=\dfrac{ln 3.86}{ln 2}

n =1.948

We need to calculate the age of living tree

Using formula of age

t=n\times t_{\frac{1}{2}}

t=1.948\times5700

t=11103.6 =11104\ years

Hence, The age of living tree is 11104 years.

5 0
3 years ago
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