Answer:
The track's angular velocity is W2 = 4.15 in rpm
Explanation:
Momentum angular can be find
I = m*r^2
P = I*W
So to use the conservation
P1 + P2 = 0
I1*W1 + I2*W2 = 0
Solve to w2 to find the angular velocity
0.240kg*0.30m^2*0.79m/s=-1kg*0.30m^2*W2
W2 = 0.435 rad/s
W2 = 4.15 rpm
Answer:
the height (in feet) of the cliff is 121 ft
Explanation:
A stone hit the cliff with
speed, v = 88 ft/s
Acceleration, a= 32 ft/s^2
initial speed, u = 0 ft/s
height is h.
To solve this problem we will apply the linear motion kinematic equations, Equation of motion describes change in velocity, depending on the acceleration and the distance traveled
so, writing the formula of Equation of motion:
v^2 - u^2 = 2*a*h
substituting the appropriate values,
(88)^2 - 0 = 2*32* h
h=(88)^2 / 64
h= 121 ft
hence
the height (in feet) of the cliff is 121 ft
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Answer:
travilng on a curve in the road
Explanation:
Answer:
the work converted to thermal energy is 40 J.
Explanation:
Given;
work done by the physicist,w = 100 J
height through which the book is raised, h = 0.2 m
efficiency of machine = 60% = 0.6
The useful work done by the machine is calculated as;
useful work = 0.6 x 100 = 60 J
The wasted energy = 100 J - 60 J
The wasted energy = 40 J
The wasted energy by the machine is possibly converted to thermal energy by the frictional part of the machine.
Therefore, the work converted to thermal energy is 40 J.
