Answer:
Since oxygen (O) has an atomic mass of 16 g, oxygen gas (O2) has a molecular mass of 2 x 16 = 32 g. We need to convert the given amount of oxygen gas to moles and this can be done by dividing the given mass by the molecular weight of oxygen gas. Hence, moles of oxygen gas = 48 g / 32 g/mole = 1.5 moles.
Explanation:
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You missed a lot of details in your question, so when we have the complete question as the attached picture so, the answer would be:
when we have the value of Ka = 1.8 x 10^-5 so, we can use it to get the Pka value
by using this formula:
Pka = -㏒Ka
= -㏒(1.8 x 10^-5)
= 4.7
now, after we have got the Pka we need now to get moles of NaC2H3O2 and
moles of HC2H3O2:
when moles of NaOH = 0.015 moles
when moles NaC2H3O2 after adding NaOH
= initial mol NaC2H3O2 + mol NaOH
∴moles NaC2H3O2 = 0.1 + 0.015 = 0.115 moles
and moles HC2H3O2 after adding NaOH
= initial mol HC2H3O2 - mol NaOH
∴ moles HC2H3O2 = 0.1 - 0.015 = 0.085 moles
so, when we have moles [HC2H3O2] &[NaC2H3O2] so we can substitution its values in [A] &[HA] :
by using H-H equation we can get the PH:
when PH = Pka + ㏒[A]/[HA] PH = 4.7 + ㏒0.115/0.085
= 4.8
Explanation:
1). The given data is as follows.
, 
C = 5.73 
Hence, calculate the change in enthalpy of the reaction as follows.
=
= -70.25 KJ
As, number of moles =
=
= 0.018 mol
Therefore, enthalpy of reaction in kJ/mol hexane is as follows.
=
kJ/mol
Thus, we can conclude that
for the reaction in kJ/mol hexane is
kJ/mol
.
2). As we know that,
Number of moles =
=
= 0.017 mol
=
= -65.875 kJ
As, 
-65.875 kJ =
C = 4.56 
Hence, heat capacity of the bomb calorimeter is 4.56
.
Answer:
C) 237.96682 amu
Explanation:
The symbol for neptunium-236 is given as;
²³⁶₉₃Np
This element has 93 protons and (236 - 93 = 143) neutrons.
Mass Number =Total mass of Protons + Total mass of neutrons
Total Mass pf protons = 93 * 1.007825 amu, = 93.727725 amu
Total mass of Neutrons = 143 * 1.008665 amu = 144.239095 amu
Mass = 144.239095 + 93.727725 = 237.96682 amu
Correct option is option C.
The total heat of hydration of 1. 00 mol of gas phase
ions and
ions is - 684 kJ/mol.
Calculation ,
Given data ,
Heat of solution = 17. 2 kJ/mol
lattice energy of KCl(s) = 701. 2 kJ/mol.
heat of hydration = ?
The KCl is formed by
ions and
– ions
Δ
= U° + Δ
Δ
= Δ
- U° = 17. 2 kJ/mol - 701. 2 kJ/mol = - 684 kJ/mol
Hence, heat of hydration of 1. 00 mol of gas phase
ions and
ions is - 684 kJ/mol.
To learn more about hydration
brainly.com/question/15724859
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