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ryzh [129]
3 years ago
14

A 12-mm-diameter cylindrical jet of water discharges vertically into the ambient air. Due to surface tension the pressure inside

the jet will be slightly higher than the surrounding atmospheric pressure. Determine this difference in pressure.

Engineering
1 answer:
navik [9.2K]3 years ago
3 0

Answer:

Explanation:

Given

Diameter of cylindrical is d=12\ mm

There is excess Pressure in the cylindrical jet which can be  calculated by using Equilibrium free body  Diagram of an element of jet

excess Pressure force will balance the Surface tension force of water jet

\Delta P\times Area=Surface\ tension \times length

\Delta P\cdot 2R\delta l=\sigma \times 2\delta l

where \sigma =surface tension of water

\Delta P=excess Pressure

R=radius

\delta l=length of element

therefore \Delta P=\frac{\sigma }{R}

Surface Tension of water is \sigma =7.34\times 10^{-2}\ N/m

\Delta P=\frac{7.34\times 10^{-2}}{6\times 10^{-3}}

\Delta P=12.23\ Pa

     

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The difference between an initial condition and a boundary condition for conduction in a solid is:___________
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c. an initial condition specifies the temperature at the start of the problem and a boundary condition provides information about temperatures on the boundaries.

Explanation:

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7 0
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12.28 LAB: Output values in a list below a user defined amount - functions Write a program that first gets a list of integers fr
Anastaziya [24]

Answer:

def output_ints_less_than_or_equal_to_threshold(user_values, upper_threshold):

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def get_user_values():

   n = int(input())

   lst = []

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   return lst  

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A fatigue test was conducted in which the mean stress was 46.2 MPa and the stress amplitude was 219 MPa.
sleet_krkn [62]

Answer:

a)σ₁ = 265.2 MPa

b)σ₂ = -172.8 MPa

c)Stress\ ratio =-0.65

d)Range = 438 MPa

Explanation:

Given that

Mean stress ,σm= 46.2 MPa

Stress amplitude ,σa= 219 MPa

Lets take

Maximum stress level = σ₁

Minimum stress level =σ₂

The mean stress given as

\sigma_m=\dfrac{\sigma_1+\sigma_2}{2}

2\sigma_m={\sigma_1+\sigma_2}

2 x 46.2 =  σ₁ +  σ₂

 σ₁ +  σ₂ = 92.4 MPa    --------1

The amplitude stress given as

\sigma_a=\dfrac{\sigma_1-\sigma_2}{2}

2\sigma_a={\sigma_1-\sigma_2}

2 x 219 =  σ₁ -  σ₂

 σ₁ -  σ₂ = 438 MPa    --------2

By adding the above equation

2  σ₁ = 530.4

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-σ₂ = 438 -265.2 MPa

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Stress\ ratio =\dfrac{\sigma_{min}}{\sigma_{max}}

Stress\ ratio =\dfrac{-172.8}{265.2}

Stress\ ratio =-0.65

Range = 265.2 MPa - ( -172.8 MPa)

Range = 438 MPa

8 0
3 years ago
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