Answer: Hello the question is incomplete below is the missing part
Question: determine the temperature, in °R, at the exit
answer:
T2= 569.62°R
Explanation:
T1 = 540°R
V2 = 600 ft/s
V1 = 60 ft/s
h1 = 129.0613 ( value gotten from Ideal gas property-air table )
<em>first step : calculate the value of h2 using the equation below </em>
assuming no work is done ( potential energy is ignored )
h2 = [ h1 + ( V2^2 - V1^2 ) / 2 ] * 1 / 32.2 * 1 / 778
∴ h2 = 136.17 Btu/Ibm
From Table A-17
we will apply interpolation
attached below is the remaining part of the solution
Answer:
a) Cr = Co - Fx / D
b) ΔC / Δx = ( CR - Cr ) / ( xR - xRo )
Explanation:
A) Derive an expression for the profile c(r) inside the tissue
F = DΔC / X = D ( Co - Cr ) / X ------ 1
where : F = flux , D = drug diffusion coefficient
X = radial distance between Ro and R
Hence : Cr = Co - Fx / D
B) Express the diffusive flux at outer surface of the balloon
Diffusive flux at outer surface = ΔC / Δx = CR - Cr / xR - xRo
Answer:
B. to lock the tape into place
Explanation:
the button on the front of the housing locks the tape into place when pressed, preventing the tape from being pulled out further it retracting
Answer:
The process of generation of force by the high speed that pushes the jet engine forward is based on Newton’s 2 law of motion ?
Explanation:
1, Newton’s first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. This postulate is known as the law of inertia.
2,
Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it. The momentum of a body is equal to the product of its mass and its velocity. Momentum, like velocity, is a vector quantity, having both magnitude and direction. A force applied to a body can change the magnitude of the momentum, or its direction, or both.For a body whose mass m is constant, it can be written in the form F = ma, where F (force) and a (acceleration)
3, Newton’s third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction.The third law is also known as the law of action and reaction. This law is important in analyzing problems of static equilibrium, where all forces are balanced, but it also applies to bodies in uniform or accelerated motion. The forces it describes are real ones, not mere bookkeeping devices. For example, a book resting on a table applies a downward force equal to its weight on the table. According to the third law, the table applies an equal and opposite force to the book.
