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3 years ago

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A 12-mm-diameter cylindrical jet of water discharges vertically into the ambient air. Due to surface tension the pressure inside

the jet will be slightly higher than the surrounding atmospheric pressure. Determine this difference in pressure.

1 answer:

navik [9.2K]3 years ago

3 0

Answer:

Explanation:

Given

Diameter of cylindrical is $d=12\ mm$

There is excess Pressure in the cylindrical jet which can be calculated by using Equilibrium free body Diagram of an element of jet

excess Pressure force will balance the Surface tension force of water jet

$\Delta P\times Area=Surface\ tension \times length$

$\Delta P\cdot 2R\delta l=\sigma \times 2\delta l$

where $\sigma =$ surface tension of water

$\Delta P=$ excess Pressure

R=radius

$\delta l=$ length of element

therefore $\Delta P=\frac{\sigma }{R}$

Surface Tension of water is $\sigma =7.34\times 10^{-2}\ N/m$

$\Delta P=\frac{7.34\times 10^{-2}}{6\times 10^{-3}}$

$\Delta P=12.23\ Pa$

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Koch traded Machine 1 for Machine 2 when the fair market value of both machines was $60,000. Koch originally purchased Machine 1

Mariana [72]

Answer:

Koch's adjusted basis in machine 2 after the exchange is $60,000

Explanation:

given data

fair market value = $60,000

originally purchased Machine 1 = $76,900

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Machine 2 adjusted basis = $55,950

solution

As he exchanged machine for another at $60,000

and this exchanged in fair market

so adjusted basis = $50,000

Adjusted basis is the price of the item that affects the factors that are considered price. These factors usually include taxes, depreciation value, and other costs of acquiring and maintaining a given item. Adjusted basis is important so the right amount to sell

Adjusted basis increases when a person deducts expenses from factor taxes and operating statements

so Koch's adjusted basis in machine 2 after the exchange is $60,000

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3 years ago

Consider a refrigerator that consumes 320 W of electric power when it is running. If the refrigerator runs only one quarterof th

ryzh [129]

Answer:

$5.184

Explanation:

The cost can be calculated using the formula: $Cost = Load \ factor \times Number \ of \ hours \ \\M_{month} = M_{units} \times W\\$

Before using this, we require the following conversions:

<em>320 W → kW:</em>

$\frac {320}{1000} = 0.32$

<em>30 Days → Hours:</em>

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2 years ago

A pipe of 0.3 m outer diameter at a temperature of 160°C is insulated with a material having a thermal conductivity of k = 0.055

Alekssandra [29.7K]

Answer:

Q=0.95 W/m

Explanation:

Given that

Outer diameter = 0.3 m

Thermal conductivity of material

$K= 0.055(1+2.8\times 10^{-3}T)\frac{W}{mK}$

So the mean conductivity

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$T_m=373 K$

$K_m=0.055\left ( 1+2.8\times 10^{-3}\times 373 \right )$

$K_m=0.112 \frac{W}{mK}$

So heat conduction through cylinder

$Q=kA\dfrac{\Delta T}{L}$

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Q=0.95 W/m

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3 years ago

A multipurpose transformer has a secondary coil with several points at which a voltage can be extracted, giving outputs of 5.60,

Rudik [331]

Answer:

for 5.6V 9 turns, for 12.0V 19 turns, for 480V 755 turns

Explanation:

Vp/Vs= Np/Ns

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Vs: Secondary Voltage

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Ns: number of turns on secondary side

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