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ryzh [129]
3 years ago
14

A 12-mm-diameter cylindrical jet of water discharges vertically into the ambient air. Due to surface tension the pressure inside

the jet will be slightly higher than the surrounding atmospheric pressure. Determine this difference in pressure.

Engineering
1 answer:
navik [9.2K]3 years ago
3 0

Answer:

Explanation:

Given

Diameter of cylindrical is d=12\ mm

There is excess Pressure in the cylindrical jet which can be  calculated by using Equilibrium free body  Diagram of an element of jet

excess Pressure force will balance the Surface tension force of water jet

\Delta P\times Area=Surface\ tension \times length

\Delta P\cdot 2R\delta l=\sigma \times 2\delta l

where \sigma =surface tension of water

\Delta P=excess Pressure

R=radius

\delta l=length of element

therefore \Delta P=\frac{\sigma }{R}

Surface Tension of water is \sigma =7.34\times 10^{-2}\ N/m

\Delta P=\frac{7.34\times 10^{-2}}{6\times 10^{-3}}

\Delta P=12.23\ Pa

     

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  1. public class Main {
  2.    public static void main(String[] args) {
  3.        String testString = "abscacd";
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  5.        String oddStr = "";
  6.        for(int i=testString.length() - 1; i >= 0; i--){
  7.            if(i % 2 == 0){
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  9.            }
  10.            else{
  11.                oddStr += testString.charAt(i);
  12.            }
  13.        }
  14.        System.out.println(evenStr + oddStr);
  15.    }
  16. }

Explanation:

Firstly, let declare a variable testString to hold an input string "abscacd" (Line 1).

Next create another two String variable, evenStr and oddStr and initialize them with empty string (Line 5-6). These two variables will be used to hold the string at even index and odd index, respectively.

Next, we create a for loop that traverse the characters of the input string from the back by setting initial position index i to  testString.length() - 1  (Line 8). Within the for-loop, create if and else block to check if the current index, i is divisible by 2, (i % 2 == 0), use the current i to get the character of the testString and join it with evenStr. Otherwise, join it with oddStr (Line 10 -14).

At last, we print the concatenated evenStr and oddStr (Line 18).  

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