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Agata [3.3K]
3 years ago
15

A room is cooled by circulating chilled water through a heat exchanger located in the room. The air is circulated through the he

at exchanger by a 0.25-hp (shaft output) fan. Typical efficiency of small electric motors driving 0.25-hp equipment is 60 percent. Determine the rate of heat supply by the fan–motor assembly to the room.
Engineering
1 answer:
Zanzabum3 years ago
6 0

Answer:

input power of the geothermal motor will be 0.4166 hP

Explanation:

We have given shaft output = 0.25 hP

hP is known as horse power which is unit of measuring the power of motor

Efficiency of motor is given as efficiency = 60 % = 0.6

We have to fond the heat supply by the fan motor Q

We know that efficiency of any motor is the ratio of shaft power and input power

So 0.6=\frac{0.25}{P_0}

So P_0=\frac{0.25}{0.6}=0.4166hP

So input power of the geothermal motor will be 0.4166 hP

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F =  8849 N

Explanation:

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σ_{fs} = F_{f} L / \pi  R^{3}

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Putting the given values in the above formula:

σ = 4250 ( 44 x 10⁻³ ) / π  ( 5.6 x 10⁻³ ) ³

  = 4250 ( 44 x 10⁻³ )  / 3.141593 ( 5.6 x 10⁻³ ) ³

  = 4250 (44 x 1 /1000 )) / 3.141593 ( 5.6 x 10⁻³ ) ³

  = 4250 ( 11 / 250  ) / 3.141593 ( 5.6 x 10⁻³ ) ³

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Now we compute the load i.e. F from the following formula:

F_{f} = 2 σ_{fs} d³/3 L

F = 2σd³/3L

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  = 2 ( 338 x 1000000 ) ( 12 x 10⁻³)³ / 3 ( 44 x 10⁻³)

  = 2 ( 338000000 ) ( 12 x 10⁻³)³ / 3 ( 44 x 10⁻³)

  = 676000000 ( 12 x 10⁻³)³ / 3 ( 44 x 10⁻³)

  = 676000000 ( 12  x  1/1000  )³ / 3 ( 44 x 10⁻³)

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  = 146016  / 125 / 3 ( 44 x 1 / 1000  )

  = ( 146016  / 125 ) /  (3 ( 11 /  250 ))

  =  97344  / 11

F =  8849 N

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The function that you will use in order to test the reverse route back toward the original host is known as Extended ping. Thus, the correct option for this question is B.

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