Answer:
<em>181 °C</em>
<em></em>
Explanation:
Initial pressure
= 100 kPa
Initial temperature
= 30 °C = 30 + 273 K = 303 K
Final pressure
= 1200 kPa
Final temperature
= ?
n = 1.2
For a polytropic process, we use the relationship
(
/
) = (
/
)^γ
where γ = (n-1)/n
γ = (1.2-1)/1.2 = 0.1667
substituting into the equation, we have
(
/303) = (1200/100)^0.1667
/303 = 12^0.1667
/303 = 1.513
= 300 x 1.513 = 453.9 K
==> 453.9 - 273 = 180.9 ≅ <em>181 °C</em>
In the case above, poor connection at the pressure cycling switch and also a faulty A/C clutch coil could be the cause.
<h3>What is likely the reason when an A/C compressor will not engage if A/C is turned on?</h3>
The cause that hinders the A/C Compressor from engaging are:
- Due to low pressure lockout.
- Due to a poor ground
- Due to bad clutch coil.
- Dur to an opening in the wire that links to the clutch coil.
- Due to a blown fuse.
Note that the pressure switches is known to be one that control the on/off function of any kind of AC compressor and as such, if there is switch failure, it can hinder the AC compressor from functioning at all.
Therefore, technician A and B are correct.
Learn more about refrigerant pressure from
brainly.com/question/10054719
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Answer:
Circular tube
Explanation:
Now for better understanding lets take an example
Lets take
Diameter of solid bar=
cm
Outer diameter of tube =6 cm
Inner diameter of tube=2 cm
So from we can say that both tubes have equal cross sectional area.
We know that buckling load is given as
If area moment of inertia(I) is high then buckling load will be high.
We know that area moment of inertia(I)
For circular tube 
For circular bar
Now by putting the values
For circular tube 
For circular bar 
So we can say that for same cross sectional area the area moment of inertia(I) is high for tube as compare to bar.So buckling load will be higher in tube as compare to bar.
Answer:
13.4 mm
Explanation:
Given data :
Load amplitude ( F ) = 22,000 N
factor of safety ( N )= 2.0
Take ( Fatigue limit stress amplitude for this alloy ) б = 310 MPa
<u>calculate the minimum allowable bar diameter to ensure that fatigue failure will not occur</u>
minimum allowable bar diameter = 13.4 * 10^-3 m ≈ 13.4 mm
<em>attached below is a detailed solution</em>