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MAXImum [283]
3 years ago
8

Write 2,469,100 in Engineering Notation with 3 significant figures.

Chemistry
1 answer:
Gala2k [10]3 years ago
6 0

Answer: 2.47\times 10^{6}

Explanation:

Engineering notation : It is the representation of expressing the numbers that are too big or too small and are represented in the decimal form times 10 raise to the power.  It is similar to the scientific notation but in engineering notation, the powers of ten are always multiples of 3.

The engineering notation written in the form:

a\times 10^b

where,

a = the number which is greater than 0 and less than 999

b = an integer multiple of 3

Now converting the given value of 2,469,100 into engineering notation, we get 2.47\times 10^{6}

Hence, the correct answer is, 2.47\times 10^{6}

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Answer:

K.E.=1.97\times 10^{-21}\ J

Explanation:

Given that:-

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The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = \frac {1}{101325} P (atm)

Given the value of pressure = 43,836 Pa

So,  

6.9\times 10^5\ Pa = \frac{6.9\times 10^5}{101325} atm

Pressure = 6.80977 atm

Volume = 2.3\times 10^{-3}\ m^3 = 2.3 L ( 1 m³ = 1000 L)

n = 2 mol

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

6.80977 atm × 2.3 L = 2 mol × 0.0821 L.atm/K.mol × T

⇒T = 95.39 K

The expression for the kinetic energy is:-

K.E.=\frac{3}{2}\times K\times T

k is Boltzmann's constant = 1.38\times 10^{-23}\ J/K

T is the temperature

So, K.E.=\frac{3}{2}\times 1.38\times 10^{-23}\times 95.39\ J

K.E.=1.97\times 10^{-21}\ J

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