How many grams are in 1.70 moles of Ca(NO3)2?

Chemistry

1 answer:

Andru [333]1 year ago

4 0

The number of grams in 1.70 moles of Ca(NO₃)₂ is 384.2 grams

<h3>How to determine the mass of Ca(NO₃)₂</h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

With the above formula, we can determine the mass of Ca(NO₃)₂ as illustrated below:

Mole of Ca(NO₃)₂ = 1.70 moles
Molar mass of Ca(NO₃)₂ = 40 + 3[14 + (16 × 3)] = 40 + 3[14 + 48] = 40 + 3(62) = 40 + 186 = 226 g/mol
Mass of Ca(NO₃)₂ = ?

Mole = mass / molar mass

1.70 = Mass of Ca(NO₃)₂ / 226

Cross multiply

Mass of Ca(NO₃)₂ = 1.70 × 226

Mass of Ca(NO₃)₂ = 384.2 grams

Thus, the mass of 1.70 moles of Ca(NO₃)₂ is 384.2 grams

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