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Butoxors [25]
3 years ago
8

A ____ has a mass of almost zero A. Proton B.Neutron C. Electron D.lon

Chemistry
1 answer:
valentina_108 [34]3 years ago
7 0

Answer:

C.electron po yung sagot

Explanation:

because electron has a 0.0005 mass

and -1 charge.

thanks me later

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The bowling ball is whizzing down the bowling lane at 4 m/s. If the mass of the bowling ball is 7 kg, what is its kinetic energy
natali 33 [55]
KE = (1/2)(m)(v^2)

KE = (1/2)(7)(4^2)

KE = (1/2)(112)

KE = 56 J
4 0
3 years ago
9. What type of bonds hold polyatomic ions together?
ella [17]
The answer is B Covalent bonds
5 0
3 years ago
Read 2 more answers
What volume (in mL) of 0.250 M HCI would be
Nitella [24]

Answer: 1820 mL (to 3 sf)

Explanation:

The atomic mass of aluminum is 26.9815385 g/mol, so 4.10 g of aluminum is equal to 4.10/26.9815385 = 0.15195575300497 moles of Al.

From the coefficients of the equation, we know that for every 2 moles of aluminum consumed, 6 moles of HCl are consumed.

So, this means we need 0.15195575300497(6/2) = 0.45586725901491 moles of HCl.

Substituting into the molarity formula,

  • 0.250 = 0.45586725901491/(liters of HCl)
  • liters of HCl = 0.45586725901491/0.250
  • liters of HCl = 1.8234690360596 L = 1820 mL (to 3 sf)
4 0
2 years ago
Which best describes the effect of j.j Thomson's discovery
goblinko [34]
The accepted model of the atom was changed. JJ Thomson discovered the electrons and performed experiment using the cathode ray tube. The model before his did not have electrons so the model was changed. Hope this helps
3 0
3 years ago
4 FeCO3 + O2 --> 2 Fe2O3 + 4CO2
Andre45 [30]

The percentage yield of the reaction : 93.3%

Mass of FeCO₃ 2310.44 g

<h3>Further explanation </h3>

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Reaction

4 FeCO₃ + O₂ ⇒ 2 Fe₂O₃ + 4CO₂

MW FeCO₃ : 115,854 g/mol

MW Fe₂O₃ : 159,69 g/mol

  • mol FeCO₃

\tt \dfrac{35}{115.854}=0.302

  • mol Fe₂O₃

\tt \dfrac{2}{4}\times 0.302=0.151

  • mass Fe₂O₃

\tt 0.151\times 159.69=24.113~g

  • percent yield

\tt \dfrac{22.5}{24.113}\times 100\%=93.3\%

mol of 1 kg Fe₂O₃ = 1000 g

\tt \dfrac{1000}{159.69}=6.262

mol of FeCO₃

\tt \dfrac{4}{2}\times 6.262=12.524

mass of FeCO₃

\tt 12.524\times 115.854=1450.955~g

a purity of 62.8%

\tt \dfrac{100}{62.8} \times 1450.955=2310.44~g

4 0
3 years ago
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