KE = (1/2)(m)(v^2)
KE = (1/2)(7)(4^2)
KE = (1/2)(112)
KE = 56 J
The answer is B Covalent bonds
Answer: 1820 mL (to 3 sf)
Explanation:
The atomic mass of aluminum is 26.9815385 g/mol, so 4.10 g of aluminum is equal to 4.10/26.9815385 = 0.15195575300497 moles of Al.
From the coefficients of the equation, we know that for every 2 moles of aluminum consumed, 6 moles of HCl are consumed.
So, this means we need 0.15195575300497(6/2) = 0.45586725901491 moles of HCl.
Substituting into the molarity formula,
- 0.250 = 0.45586725901491/(liters of HCl)
- liters of HCl = 0.45586725901491/0.250
- liters of HCl = 1.8234690360596 L = 1820 mL (to 3 sf)
The accepted model of the atom was changed. JJ Thomson discovered the electrons and performed experiment using the cathode ray tube. The model before his did not have electrons so the model was changed. Hope this helps
The percentage yield of the reaction : 93.3%
Mass of FeCO₃ 2310.44 g
<h3>Further explanation
</h3>
The reaction equation is the chemical formula of reagents and product substances
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products
Reaction
4 FeCO₃ + O₂ ⇒ 2 Fe₂O₃ + 4CO₂
MW FeCO₃ : 115,854 g/mol
MW Fe₂O₃ : 159,69 g/mol




mol of 1 kg Fe₂O₃ = 1000 g

mol of FeCO₃

mass of FeCO₃

a purity of 62.8%
