What will be the net force acting upon this object?
1 answer:
To determine the net force acting upon an object we need to do the vector addition of the forces acting on it.
In this case we have two forces, one acting to the left and one to the right. We need to establish which of this ways is the positive direction. Let's assume the right direction is the positive direction; for this convention the 20 N forces is positve and the 10 N is positive; then the net force would be:
Since the resulting net force is positive this means, for our convention, that the net force points in the right direction. Therefore, the net force is 10 N to the right.
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Fission reaction is given
¹₀n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3(¹₀n)
The atomic masses of the fission products are 97.912735 u for ⁹⁸₄₀Zr and 134.916450 u for ¹³⁵₅₂Te. Hence, the energy released in fission reaction is 191.715 MeV.
How to find the energy released in the given fission reaction?
We know, that the atomic mass of the elements are as follows:
- ⁹⁸₄₀Zr - 97.9120u
- ¹³⁵₅₂Te - 134.9087u
- ²³⁵₉₂U - 235.0483923u
- n = 1.008665u
In order to find the mass difference, we will calculate the initial mass and the mass of products.
The equation for the reaction:
n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3n
Mass of initial reagents is 1.008665u + 235.0483923u = 233.052588u
Product of the reagents is 97.9120u + 134.9087u + 3(1.008665u) = 235.846773u
Now, using the formula of
Hence, the energy released in fission reaction is 191.715 MeV.
To learn more about fission reactor, refer to:
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Answer:
20 N
Explanation:
There are two forces acting on the box:
- The force of push, F, forward, of magnitude F = 20 N
- The force of friction, , backward
So, the equation of motion for the box is
where
m = 5.0 kg is the mass of the box
a is its acceleration
The box is sliding at constant velocity: this means that its acceleration is zero
a = 0
So, the equation becomes
Therefore, we can find the magnitude of the force of friction: