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Vaselesa [24]
3 years ago
7

determine the angle and the magnitude of force f so that the resultant force acting on the post is directed vertically upward an

d has a magnitude of 750 n

Physics
2 answers:
xenn [34]3 years ago
5 0

Answer / Explanation:

To solve this question,

Let us recall the Sine Rule and assuming we have an angle of θ.

Then it states thus:

sin θ / 750

Therefore, Sin 30⁰/ 700

: θ / 750 = Sin 30⁰/ 700

θ = 36.87  

Now that we have θ, we can figure out ∅

Therefore,

∅ = 180°  − (30 °  + 36.87° )

Recalling that all interior angles in a triangle must add up to 180°

Therefore,

∅ = 113.13°

Now that we have both θ and ∅, we can go further to use the law of sines to find Fr.

Therefore,

Fr/Sin 113.13° = 700 / Sin 30 °

Fr = 919.61 Newton

Vlad1618 [11]3 years ago
4 0

Answer:

The force F = 318 and the angle 18.5°. The first thing to do is to resolve the forces into components along the x and y-axis and then equate it to Rx and Ry. R has no component along the x-axis since it is directed along the y-axis.

Explanation:

The detailed solution can be found in the attachment below. Thank you for reading.

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A dog pulls on a pillow with a force of 5 N at an angle of 37o to the horizontal. Find the x and y components of this force.​
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Answer:

x- component = Fx= 4N

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the dog pulls the pillow at an angle 37 degrees to the horizontal means it pulls it at an angle 37 degrees with the x- axis.if  the line of the force represents the vector F then its horizonatal and vertical components wil be along x-axis and y-axis ie Fx and Fy.

as sin∅= Perpendicular/ Hypotenuse

but we have force F and Fy

so sin∅= Fy/F

or Fy= Fsin∅---------eqA

similarly cos∅= base /hpotenuse

cos∅= Fx/F

Fx= Fcos∅----------eq B

eq A  and eq B can be used to determine the values of the rectangular components of the force making an angle with the horizontal

5 0
3 years ago
Estimate the frequency of vibration of your arm.
Natali5045456 [20]

Answer:

0.7945 Hz

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Since the center of mass lies at about \frac{2}{3} of its length

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Length of the simple pendulum = \frac{2}{3} × 0.59 m = 0.3933 m

Now,

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Thus,

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Frequency of vibration for the arm = \frac{1}{2\pi}\sqrt\frac{9.8}{0.3933}

or

Frequency of vibration for the arm = 0.7945 Hz

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that is the definition of work

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