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Vaselesa [24]
3 years ago
7

determine the angle and the magnitude of force f so that the resultant force acting on the post is directed vertically upward an

d has a magnitude of 750 n

Physics
2 answers:
xenn [34]3 years ago
5 0

Answer / Explanation:

To solve this question,

Let us recall the Sine Rule and assuming we have an angle of θ.

Then it states thus:

sin θ / 750

Therefore, Sin 30⁰/ 700

: θ / 750 = Sin 30⁰/ 700

θ = 36.87  

Now that we have θ, we can figure out ∅

Therefore,

∅ = 180°  − (30 °  + 36.87° )

Recalling that all interior angles in a triangle must add up to 180°

Therefore,

∅ = 113.13°

Now that we have both θ and ∅, we can go further to use the law of sines to find Fr.

Therefore,

Fr/Sin 113.13° = 700 / Sin 30 °

Fr = 919.61 Newton

Vlad1618 [11]3 years ago
4 0

Answer:

The force F = 318 and the angle 18.5°. The first thing to do is to resolve the forces into components along the x and y-axis and then equate it to Rx and Ry. R has no component along the x-axis since it is directed along the y-axis.

Explanation:

The detailed solution can be found in the attachment below. Thank you for reading.

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Tensile stress is: A. the strain per unit length. B. the ratio of elastic modulus to strain. C. the ratio of the change in lengt
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If the earth's magnetic field has strength 0.50 gauss and makes an angle of 20.0 degrees with the garage floor, calculate the ch
lys-0071 [83]

Answer:

ΔΦ = -3.39*10^-6

Explanation:

Given:-

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- The radius of the coil r = 19 cm

Find:

calculate the change in the magnetic flux δφb, in wb, through one of the loops of the coil during the rotation.

Solution:

- The change on flux ΔΦ occurs due to change in angle θ of earth's magnetic field B and the normal to circular coil.

- The strength of magnetic field B and the are of the loop A remains constant. So we have:

                         Φ = B*A*cos(θ)

                         ΔΦ = B*A*( cos(θ_1) - cos(θ_2) )

- The initial angle θ_1 between the normal to the coil and B was:

                         θ_1  = 90° -  ∅

                         θ_1  = 90° -  20° = 70°

The angle θ_2 after rotation between the normal to the coil and B was:

                         θ_2  =  ∅

                         θ_2  = 20°

- Hence, the change in flux can be calculated:

                        ΔΦ = 0.5*10^-4*π*0.19*( cos(70) - cos(20) )

                        ΔΦ = -3.39*10^-6

                       

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