<h3>
Answer:</h3>
0.35 M
<h3>
Explanation:</h3>
<u>We are given;</u>
- Initial volume as 35.0 mL or 0.035 L
- Initial molarity as 12.0 M
- Final volume is 1.20 L
We are required to determine the final molarity of the solution;
- Dilution involves adding solvent to a solution to make it more dilute which reduces the concentration and increases the solvent while maintaining solute constant.
- Using dilution formula we can determine the final molarity.
M1V1 = M2V2
M2 = M1V1 ÷ V2
= (12.0 M × 0.035 L) ÷ 1.2 L
= 0.35 M
Thus, the final concentration of the solution is 0.35 M
Answer:- 3. 
and 
Explanations:- An empirical formula is the simplest whole number ratio of atoms of each element present in the molecule/compound.
For example, the molecular formula of benzene is 
. The ratio of C to H in it is 6:6 that could be simplified to 1:1. So, an empirical formula of benzene is CH.
In the first pair, the ratio of C to H in first molecule is 2:4 that could be simplified to 1:2 and the empirical formula is 
. In second molecule the ratio of C to H is 6:6 and it could be simplified to 1:1. and the empirical formula is CH. Empirical formulas are different for both the molecules of first pair and so it is not the right choice.
In second pair, C to H ratio in first molecule is 1:2, so the empirical formula is . The C to H ratio for second molecule is 1:4, so the empirical formula is 
. Here also, the empirical formulas are not same and hence it is also not the right choice.
In third pair, C to H ratio in first molecule is 1:3, so the empirical formula is . In second molecule the C to H ratio is 2:6 and it is simplified to 1:3. So, the empirical formula for this one is also . Hence. this is the correct choice.
In fourth pair, first molecule empirical formula is CH. Second molecule has 2:4 that is 1:2 mole ratio of C to H and so its empirical formula is . As the empirical formulas are different, it is not the right choice.
So, the only and only correct pair is the third one. 3. and
C-Cl bond is polar.
As Cl is more electronegative than C,
Cl pulls the shared electrons towards its side making the C-Cl bond polar.
Polar meaning C gets a partial positive charge and Cl gets a partial negative charge. Thus C-Cl bond becomes polar.
CCl4 molecule is tetrahedral.
And its shape is symmetrical.
That means its similar on all corners or all planes and it can be cut into equal halves from any plane.
C-Cl bond is polar.But the C-Cl polairty gets cancelled out as its pulled equally from all sides.
Since the molecule is symmetrical CCl4 is non polar.
the answer is true the first one
Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.
- In order to respond to this query, we must decide whether a peptide bond or an aromatic side chain is demonstrating an electronic exited state that is more closely related to the ground state in terms of energy.
- When our energy is as low as possible, we are in the ground state.
- What I want to point out is that if we can choose between the two options—peptide bond or aromatic side chain—without knowing the specific reasons, we can immediately rule out two potential answers.
- Consider what we already know about energy, we have:
E = h x c/λ
- That indicates that when we have more energy, a wavelength decreases. Lower energy corresponds to higher wavelength.
- Aromatic side chains absorb between 250 and 290 nm, while peptide bonds do so between 190 and 250 nm.
- According to our breakdown, we have an electron excited state that is more closely related to the ground state in terms of energy as wavelength increases.
Thus, Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.
To view similar questions about energy, refer to:
brainly.com/question/14483627
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