Answer:
The answer to your question is 7.4 moles of Aluminum
Explanation:
Data
moles of Al = ?
moles of Al₂O₃ = 3.7
Balanced chemical reaction
4 Al + 3 O₂ ⇒ 2 Al₂O₃
To solve this problem use proportions and cross multiplication. Use the coefficients of the balanced chemical equation.
4 moles of Aluminum ----------------- 2 moles of Al₂O₃
x ----------------- 3.7 moles of Al₂O₃
x = (3.7 x 4) / 2
x = 14.8 / 2
x = 7.4 moles of Aluminum
The question does not provide the equation
Answer:-
72.89 grams
Explanation:-
The balanced chemical equation for this reaction is
CuSO4 + Fe --> FeSO4 + Cu
Molecular weight of CuSO4 = 63.55 x 1 + 32 x 1 + 16 x 4
= 159.55 gram
Atomic weight of Cu = 63.55 gram.
According to the balanced chemical equation
1 CuSO4 gives 1 Cu
∴159.55 gram of CuSO4 would give 63.55 gram of Cu.
183 gram of CuSO4 would give 63.55 x 183 / 159.55
= 72.89 grams of Cu
Answer:are there any answer option? cause i know but i have to make sure
Explanation:
First step is to balance the reaction equation. Hence we get
P4 + 5 O2 => 2 P2O5
Second, we calculate the amounts we start with
P4: 112 g = 112 g/ 124 g/mol – 0.903 mol
O2: 112 g = 112 g / 32 g/mol = 3.5 mol
Lastly, we calculate the amount of P2O5 produced.
2.5 mol of O2 will react with 0.7 mol of P2O5 to produce 1.4
mol of P2O5.
This is 1.4 * (31*2 + 16*5) = 198.8 g
