Answer:
Mass percent concentration: 25,2% m/m
Explanation:
The percentage mass by mass indicates the grams of solute in 100 grams of solution. We convert the ml of water into g from the density formula:
δ= m/v m=δx v= 1 g/ml x 115 ml= 115 g
115g solution-----29 g NaCl
100g solution----x=(100g solutionx29 g NaCl)/115g solution
x=25,2173913 g NaCl
I believe what you are looking for is Fusion<span />
There are two H2 .There are four nitrogen atoms present. There are two NH3 formed
The number of mole of nitrogen gas, N₂, needed to produce 150 g of ammonia, NH₃ is 4.41 moles
<h3>How to determine the mole of NH₃ produced </h3>
- Mass of NH₃ = 150 g
- Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
Mole = mass /molar mass
Mole of NH₃ = 150 / 17
Mole of NH₃ = 8.82 moles
<h3>How to determine the mole of N₂ needed </h3>
Balanced equation
N₂ + 3H₂ —> 2NH₃
From the balanced equation above,
2 moles of NH₃ were produced by 1 mole of N₂.
Therefore,
8.82 moles of NH₃ will be produced by = 8.82 / 2 = 4.41 moles of N₂.
Thus, 4.41 moles of N₂ is needed for the reaction.
Learn more about stoichiometry:
brainly.com/question/14735801
