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andreyandreev [35.5K]
3 years ago
15

Hydrocarbons separated by fractional distillation of petroleum can be cracked to make

Chemistry
1 answer:
lana66690 [7]3 years ago
8 0

Answer:

c.hg cannot be cracked for fractional distillation as there is only one of each

Explanation:

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The element hydrogen adom is made up of wich kinds of adams
egoroff_w [7]

the element hydrogen atom is made up of oxygen atoms.

3 0
3 years ago
Please match the example with the classification of matter in which it belongs. Column A 1. soil: soil 2. chocolate milk: chocol
bekas [8.4K]

Answer:

34

Explanation:

add

8 0
3 years ago
You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the
Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate  reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

8 0
3 years ago
The change in entropy, Δ S ∘ rxn , is related to the the change in the number of moles of gas molecules, Δ n gas . Determine the
rewona [7]

Answer:

The entropy decreases.

Explanation:

The change in the standard entropy of a reaction (ΔS°rxn) is related to the change in the number of gaseous moles (Δngas), where

Δngas = n(gaseous products) - n(gaseous reactants)

  • If Δngas > 0, the entropy increases
  • If Δngas < 0, the entropy decreases.
  • If Δngas = 0, there is little or no change in the entropy.

Let's consider the following reaction.

2 H₂(g) + O₂(g) ⟶ 2 H₂O(l)

Δngas = 0 - 3 = -3, so the entropy decreases.

8 0
3 years ago
What is the percent composition of Sb2F3.What is the percent composition of F in this molecule? Round the answer to five signifi
poizon [28]

Answer:

\%F=18.967\%

Explanation:

Hello,

In this case, a percent composition is computed by considering the atomic mass of each element in the compound as well as the number of atoms and the molar mass of the compound. Thus, Sb2F3 has a molar mass of 300.52 g/mol, antimony has an atomic mass of 121.76 g/mol and fluorine 19.0 g/mol, therefore, the percent composition of fluorine which has three atoms with five significant figures is:

\% F=\frac{3*19.0g/mol}{300.52g/mol}*100\%\\ \\\%F=18.967\%

Best regards.

3 0
3 years ago
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