Answer:
7.46×10⁻⁶ m
Explanation:
Applying,
F = kqq'/r²............ Equation 1
make r the subject of the equation
r = √(F/kqq').......... Equation 2
From the question,
Given: F = 8 N, q' = q= 4 C
Constant: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation 2
r = √[8/(4×4×8.98×10⁹)]
r = √(55.7×10⁻¹²)
r = 7.46×10⁻⁶ m
<h2>
Velocity at maximum height is zero.</h2><h2>Acceleration at maximum height is 9.81 m/s² downward.</h2><h2>Acceleration when it just hits the ground is 9.81 m/s² downward.</h2>
Explanation:
For a ball thrown vertically upward, the velocity at maximum height is zero.
Acceleration is a constant for a ball thrown vertically upward, its is acceleration due to gravity.
Acceleration at maximum height is 9.81 m/s² downward.
Acceleration when it just hits the ground is 9.81 m/s² downward.
Answer:
the final velocity of the two blocks is 
the distance that A slides relative to B is 
Explanation:
From the diagram below;
acceleration of A relative to B is : 
where
v = u + at
Making t the subject of the formula; we have:
which implies the distance that A slides relative to B.
The final velocities of the two blocks can be determined as follows:
v = u + at
Thus, the final velocity of the two blocks is
Answer:
Its an exercise for your body
Explanation:
