Answer:
Explanation:
a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s.
F = M x 48
Mass M = F / 48
a )
When force = 2F and mass = M
Acceleration = force / mass
= 2F /F/48
= 48 X 2 = 96 cm/s²
b )
When force = F and mass = 2M
Acceleration = force / mass
= F /2F/48
= 24 cm/s²
c )
When force = 2F and mass = 2M
Acceleration = force / mass
= 2F /2F/48
= 48 cm/s
d )
When force = 2F and mass = 4M
Acceleration = force / mass
= 2F /4F/48
= 24 cm/s
e)
When force = 4F and mass = 2M
Acceleration = force / mass
= 4F / 2M
= 4F / 2 F/48
= 48 x 2
Acceleration = 96 cm/s²
The phases of the Moon and Venus
We need to draw a coordinates. the east and south should be the north vector for horizontal line 50 KM in distance is zero. the south is a negative. the south east and north west we should draw the 45 degrees angle in the approprate quadrant and then use the 1-1-sqrt(2) have a relationship in 45-45-90 triangles to resolve the N/S, E/W components.
hope this help
Answer:
a) p = m1 v1 + m2 v2
, b) dp / dt = m1 a1 + m2 a2
, c) It is equivalent to force
dp / dt = 0
Explanation:
In this problem we have two blocks and the system is formed by the two bodies.
Part A. Initially they ask us to find the moment of the whole system
p = m1 v1 + m2 v2
Part B.
Find the derivative
dp / dt = m1 dv1dt + m2 dv2 / dt
dp / dt = m1 a1 + m2 a2
Part C.
Let's analyze the dimensions
m a = [kg] [m / s2] = [N]
It is equivalent to force
Part d
Acceleration is due to a net force applied
Part e
The acceleration of block 1 is due to the force exerted by block 2 during the moment change
Part f
Force of block 1 on block 2
True f12 = m1a1 f21 = m2a2
Part g
By the law of action and reaction are equal magnitude F12 = f21
Part H
dp / dt = 0
Isolated system F12 = F21 and the masses are constant. The total moment is only redistributed
The tension of cold icebergs rubbing creates heat and it can also be how large the quantity is
