To solve this problem we will apply the work theorem which is expressed as the force applied to displace a body. Considering that body strength is equivalent to weight, we will make the following considerations



Work done to upward the object



Horizontal Force applied while carrying 10m,


Height descended in setting the child down




For full time, assuming that the total value of work is always expressed in terms of its symbol, it would be zero, since at first it performs the same work that is later complemented in a negative way.
Answer:
<em><u>Here's a list of the 10 most common mistakes </u></em>we humans make when operating an automobile.
Crossing Lanes While Turning.
Using Your Daylights At Night. ...
Bad Seating Position. ...
Riding The Brakes. ...
Leaving Your High Beams On. ...
Not Using Your Turn Signal. ...
Driving Slowly In The Passing Lane. ...
Not Adjusting The Mirrors Properly. ...
Answer:
If lone pairs of electrons, electrons not bonded to other atoms, are located in the molecule, this will change the molecular geometry, not the electron geometry. If all the electron groups are bonded, with no lone pairs, then the electron geometry and molecular geometry are the same.
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Answer:
Magnitude of gravitational force of the electron= 3.74×10^12N
Explanation:
Felectron= Fgravitational
Therefore:
Felectron/Fgravitational = kq^2/r^2 ×(r^2/Gm^2)
= kq^2/Gm^2
Where G= gravitational constant
m = mass of electron=9.1×10^-31
K= 8.9x10^9
q= 1.6×10^-19
Magnitude of gravitational force= (8.9×10^9)×(1.6×10^-19)^2/(6.7×10^-11)×(9.1×10^-31)
=( 2.2784×10^-28) / ( 6.097×10^-41)
= 3.74×10^12N