Explanation:
Let us assume that piece 1 is 
is facing west side. And, piece 2 is 
facing south side.
Let 
= m and 
= 2m. Hence,
= 10.5 m/s
= 10.5 m/s
= 
= 14.84 m/s
or, = 15 m/s
Hence, the speed of the third piece is 15 m/s.
Now, we will find the angle as follows.
= 
= 
= 
Therefore, the direction of the third piece (degrees north of east) is north of east.
Answer:
As animals get older, their bodies begin to change as well as their instincts and priorities. They get bigger and might adapt or develop.
3. The sum of the players' momenta is equal to the momentum of the players when they're stuck together:
(75 kg) (6 m/s) + (80 kg) (-4 m/s) = (75 kg + 80 kg) v
where v is the velocity of the combined players. Solve for v :
450 kg•m/s - 320 kg•m/s = (155 kg) v
v = (130 kg•m/s) / (155 kg)
v ≈ 0.84 m/s
4. The total momentum of the bowling balls prior to collision is conserved and is the same after their collision, so that
(6 kg) (5.1 m/s) + (4 kg) (-1.3 m/s) = (6 kg) (1.5 m/s) + (4 kg) v
where v is the new velocity of the 4-kg ball. Solve for v :
30.6 kg•m/s - 5.2 kg•m/s = 9 kg•m/s + (4 kg) v
v = (16.4 kg•m/s) / (4 kg)
v = 4.1 m/s
Answer:
avriage force F = 2722.5 N
Explanation:
For this problem we can use Newton's second law, to calculate the average force and acceleration we can find it by kinematics.
vf² = v₀² - 2 ax
The final carriage speed is zero (vf = 0)
0 = v₀² - 2ax
a = v₀² / 2x
a = 1.1²/(2 0.200)
a = 3.025 m / s²
a = 3.0 m/s²
We calculate the average force
F = ma
F = 900 3,025
F = 2722.5 N
Answer:
Heat required = mass× latent heat Q = 0.15 × 871 ×
