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MArishka [77]
3 years ago
13

Desde el punto A sale un vehículo a 80 km/h al mismo tiempo sale un ciclista a 20km/h ¿a qué distancia se encuentra uno del otro

al cabo de 5h. R:300k
Physics
1 answer:
stiv31 [10]3 years ago
4 0

Answer:

Distance between them after 5 hours is 300 km.

Explanation:

From point A a vehicle leaves at 80 km / h at the same time a cyclist leaves at 20 km / h at what distance is they from each other after 5 hours.

Distance traveled by A in 5 hours = speed x time = 80 x 5 = 400 km

Distance traveled by B in 5 hours = speed x time = 20 x 5 = 100 km

The distance between them after 5 hours =  400 - 100 = 300 km

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he absolute potential at a distance of 2.0 m from a positive point charge is 100 V. What is the absolute potential 4.0 m away fr
lorasvet [3.4K]

Answer:

50 V

Explanation:

The formula electric potential is given as,

V = kq/r............. Equation 1

q = Vr/k ................. Equation 2

Where q = charge at that point, V = Electric potential, k = coulombs constant, r = distant.

Given: V = 100 V, r = 2.0 m, k = 9.0×10⁹ Nm/C².

Substitute into equation 1

q = (100×2)/(9.0×10⁹ )

q = (200/9)(10⁹)

q = 22.22×10⁻⁹

q = 2.22×10⁻⁸ C.

The potential at point 4.0 m

Given: r = 4.0 m, q = 2.22×10⁻⁸ C, k = 9.0×10⁹ Nm²/C²

Substitute into equation 2

V = 9.0×10⁹(2.22×10⁻⁸)/4

V = 49.95 V

V ≈ 50 V

Hence the potential = 50 V

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3 years ago
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How can friction help you in your daily life?
11Alexandr11 [23.1K]

Answer: friction can help you in many ways such as when you hit the brakes on your car or when you are washing your face

Explanation:

friction happens in just about everything you do

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3 years ago
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Which describes the electric field at the center of a ring of uniform negative charge?.
Bingel [31]

Answer:

A negatively charged particle -q is placed at the center of a uniformly charged ring, where the ring has a total positive charge Q as shown in the following figure. The particle, confined to move along the x axis, is moved a small distance x along the axis ( where x << a) and released. Show that the particle oscillates in simple harmonic motion with a frequency given by,

7 0
2 years ago
If the weight of a submerged object is equal to the buoyant force, what net force acts upon the object?
Y_Kistochka [10]

Answer:

A

Explanation:

The weight is acting downwards where as the buoyant force acting upwards (opposite) direction with equal amount of force. so the opposite forces cancel out each other (because of the force amount being equal) and no net force is acting on the object.

Hope i have helped you

Thanks.

7 0
3 years ago
A model air rocket with a mass of 50.g is free to travel along a horizontal track. It begins from rest. After 2.0s, the rocket h
katen-ka-za [31]

Answer:

v_r=5.89\ m.s^{-1}

Explanation:

Given:

  • mass of rocket, m_r=50\ g
  • time of observation, t=2\ s
  • mass lost by the rocket by expulsion of air, m_a=10\%\ of m_r=5\ g
  • velocity of air, v_a=53\ m.s^{-1}

<u>Now the momentum of air will be equal to the momentum of rocket in the opposite direction: </u>(Using the theory of elastic collision)

m_a.v_a=(m_r-m_a)\times v_r

5\times 53=(50-5)\times v_r

v_r=5.89\ m.s^{-1}

7 0
3 years ago
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