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ipn [44]
1 year ago
6

flammable liquid is being pumped out of a drum into a bucket using a hand pump. describe an appropriate grounding and bonding pr

ocedure.
Chemistry
1 answer:
lutik1710 [3]1 year ago
3 0

When transferring flammable liquids from storage drums to smaller electrically conductive containers, bonding and grounding are required. In any workplace, you should do the same whenever you move these liquids between conductive containers.

<h3>What exactly occurs in this case?</h3>

Ground dispensing drums in the area for storing and dispensing flammable liquids. Connecting the container to an already grounded, electrically conductive object grounds it. This could be a grounded metal construction framework, a buried metal plate, a metallic subsurface gas piping system, or metal water pipes. Sparks are prevented from discharging by bonding the two containers together and grounding one of them. All connections for bonding and grounding must be made from bare metal to bare metal.

To know more about Flammable liquids, visit-brainly.com/question/3702349

#SPJ4

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If the pH of a solution is 5, what is the pOH?
butalik [34]

Answer:

The answer is 9

Explanation:

To answer this question, we are using the formula

pH + pOH = 14

It's a constant formula

We've been given the pH to be 5

So therefore, inserting it into the above above

5+ pOH = 14

pOH = 14-5

= 9

pOH = 9

That's the final answer

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3 years ago
Please can someone help I will mark brainiest!
vazorg [7]

Answer:

2Cl- ⇒ Cl ↓2+ 2e

Explanation: sorry if this is not what you were looking for.

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4 years ago
What is a process of reacting an acid with a base until an equivalence point is reached
Brrunno [24]
TITRATION is the process of reaching equilibrium between acids and bases.
8 0
3 years ago
Ethylene oxide (EO) is prepared by the vapor-phase oxidation of ethylene. Its main uses are in the preparation of the antifreeze
Rashid [163]

Answer:

a. ΔH^0_{rxn} = -108.0\frac{kJ}{mol}

b. 320.76° C

Explanation:

a.)

we can solve this type of question (i.e calculate ΔH^0_{rxn} , for the gas-phase reaction )  using the Hess's Law.

ΔH^0_{rxn} =  E_{product} deltaH^0_{t}-E_{reactant} deltaH^0_{t}

Given from the question, the table below shows the corresponding  ΔH^0_{t}(kJ/mol) for each compound.

Compound                    H^0_{t}(kJ/mol)

Liquid EO                       -77.4

CH_4_(g_)                            -74.9                

CO_(g_)                              -110.5

If we incorporate our data into the above previous equation; we have:

ΔH^0_{rxn} = (-110.5 kJ/mol + (-74.9 kJ/mol) ) - (-77.4 kJ/mol)

          =   -108.0 \frac{kJ}{mol}

b.)

We are to find the final temperature if the average specific heat capacity of the products is 2.5 J/g°C

Given that:

the specific heat capacity (c) = 2.5 J/g°C

T_{initial} = 93.0°C   &

the  enthalpy of vaporization  (ΔH^0_{vap}) = 569.4 J/g

If, we recall; we will remember that; Specific Heat Capacity is the amount of heat needed to raise the temperature of one gram of a substance by one kelvin.

∴ the specific heat capacity (c) is given as =  \frac{Heat(q)}{mass*changeintemperature(T_{initial}-T_{final})}

Let's not forget as well, that  ΔH^0_{vap} = \frac{q}{mass}

If we substitute  ΔH^0_{vap}  for  \frac{q}{mass} in the above equation, we have;

specific heat capacity (c) = \frac{deltaH^0_{vap}}{T_{final}-T_{initial}}

Making (T_{final}- T_{initial}) the subject of the formula; we have:

T_{final}- T_{initial}  = \frac{delat H^0_{vap}}{specificheat capacity}

(T_{final}-93.0^0C)=\frac{569.4J/g}{2.5J/g^0C}

T_{final}=\frac{569.4J/g}{2.5J/g^0C}+93.0^0C

         = 227.76°C +93.0°C

          = 320.76°C

∴ we can thereby conclude that the final temperature = 320.76°C                

7 0
3 years ago
How to separate unreacted iron
taurus [48]

Answer:

through magnetization

6 0
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