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Jobisdone [24]
1 year ago
15

Alice runs a website that has gotten quite popular. However, its popularity seems to have peaked, and the site is now getting 8%

fewer hits each week. If Alice's site got 42,451 hits this week, how many weekly hits can she expect it to get 10 weeks from now?If necessary, round your answer to the nearest whole number.
Mathematics
1 answer:
Elis [28]1 year ago
5 0

The website's hits are dropping at 8% per week. To determine how many weeks she will have in 10 weeks you have to determine an exponential equation:

y=a(1-r)^x

Where

x is the time in weeks

r is the decrease rate expressed as a decimal value

a is the initial value

y is the number of hits after x weeks

Considering the starting value a=42,451, and the decrease rate as r=8/100=0.08 you can determine the exponential equation that models this situation as follows:

\begin{gathered} y=42,451(1-0.08)^x \\ y=42,451(0.92)^x \end{gathered}

Replace the equation with x=10

\begin{gathered} y=42,451(0.92)^{10} \\ y=18,440.22\to18,440 \end{gathered}

She can expect to get 18,440 hits in 10 weeks

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Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
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Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

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