Answer:

Explanation:
The Coulomb's Law gives the force by the charges:

Let us denote the positon of the charge q on the y-axis as 'y'.
The force between 'Q' and'q' is

where Θ is the angle between
and x-axis.

whereas

Finally, the x-component of the net force is

There are two equal forces of gravity between the Earth and the Moon.
One force pulls the Moon toward the Earth.
The other force pulls the Earth toward the Moon.
If only this gravity suddenly switched off, then the moon would
continue to orbit the Sun, very much as it does now.
If ALL gravity suddenly switched off, then . . .
-- the Moon would stop orbiting the Earth and would sail away, in
a straight line and at the speed it had when gravity disappeared;
-- the Earth would stop orbiting the Sun and would sail away, in
a straight line and at the speed it had when gravity disappeared;
-- all the gases surrounding the Earth ... which we call "air" ... would
start drifting away, and expanding into a giant cloud of gas, and stop
being an atmosphere;
-- the Sun would completely fall apart, expand into a giant cloud of gas,
and stop being a star.
Recall the force applied to a spring and its extension/compression:
F = kΔx
Δx is the change in the spring's length (measured from its original length).
x = 0.7 m
x₀ = 0.4 m
Δx = x-x₀ = 0.7 m - 0.4 m = 0.3 m
F = 23 N
Substitute and solve for k:
23 = k×0.3
<h3>k = 7.67 N/m</h3>
Velocity is 6.9 x 1.5 = 10.35 m/s due South
- 187.237 km/hr fast is θ changing 12 min after the plane passes over the radar station
<u>Explanation:</u>
Let the distance x and angle θ be defined as in the figure below. Then

Now, differentiate with respect to t, we get

Now, calculate the travel distance from radar station to plane after 12min
Distance, 
Substituting ‘x’ value, we get

Find the rate of change of theta after 12 min,

We know, the formula for,

So, then, 




When express the value in km/he, we get, the change in theta as
