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4 years ago

What is a real life situation that demonstrates 1st Newton law for an object in move?

1 answer:

4 0

Put your math or physics textbook on the table, and just leave it there. Notice how it doesn’t move. Newton’s first law states simply that an object at rest will stay at rest, and an object in motion will stay in motion *when acted on by an outside force*. To see this in action, apply a force (a push) to the textbook and notice how (unsurprisingly) it starts moving! When you stop pushing, the textbook stops, too. This seems to violate Newton’s first law, but it’s actually because there’s another force at play pushing back: friction.

In the case of the textbook, the force you applied with the push was necessary to overcome the force of friction to get it moving, but if you were to give a textbook that same push in space, it would just drift on in a straight line at the same speed for as long as it took for something else to push on or pull at it.

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A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the wate

lilavasa [31]

Take the stone's position at ground level to be the origin, and the downward direction to be negative. Then its position in the air $y$ at time $t$ is given by

$y=100\,\mathrm m-\dfrac g2t^2$

Let $d$ be the depth of the well. The stone hits the bottom of the well after 5.00 s, so that

$-d=100\,\mathrm m-\dfrac g2(5.00\,\mathrm s)^2\implies d=\boxed{22.6\,\mathrm m}$

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3 years ago

A steel marble with 0.05 kg of mass starts from rest and rolls down a ramp. It travels 0.25 m in 1.2 seconds. Find the force act

emmasim [6.3K]

After finding acceleration, it is found that 0.02 N of force is acting on the marble

<h3>What is Force ?</h3>

Force can simply be defined as a pull or push. It is the product of mass and acceleration of the object. It is a vector quantity and it is measured in Newton.

Given that a steel marble with 0.05 kg of mass starts from rest and rolls down a ramp. It travels 0.25 m in 1.2 seconds.

The parameters to consider are;

m = 0.05 Kg

u = 0

s = 0.25 m

t = 1.2 s

a = ?

F = ?

Before we find the force acting on the marble, let us first find the acceleration by using the formula: s = ut + 1/2at²

Substitute all the parameters into the formula

0.25 = 0 + 1/2 × a × 1.2²

0.25 = 1/2 × a × 1.44

0.25 = 0.72a

a = 0.25/0.72

a = 0.35 m/s²

The force acting on the marble will be ;

F = ma

F = 0.05 × 0.35

F = 0.017

F = 0.02 N

Therefore, the force acting on the marble is 0.02 N

Learn more about Force here: brainly.com/question/388851

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1 year ago

Lila is a track and field athlete. She must complete four laps around a circular track. The track itself is a 400 meter track an

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Answer: A. Her speed is 4.4 m/s, and her velocity is 0 m/s.

Explanation: i took the test on edgenuity

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3 years ago

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The hypothesis because its very hard to make and it confounds me

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Is there a multiple choice?

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