The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.
Where,
Depth of glass
Refraction index of water
Refraction index of glass
Refraction index of air
Depth of water
I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to
Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm
Answer:
5 years worth of work (aka all of the homework i currently have)
Answer:
24.57 revolutions
Explanation:
(a) If they do not slip on the pavement, then the angular acceleration is
(b) We can use the following equation of motion to find out the angle traveled by the wheel before coming to rest:
where v = 0 m/s is the final angular velocity of the wheel when it stops, 
= 95rad/s is the initial angular velocity of the wheel, 
is the deceleration of the wheel, and 
is the angle swept in rad, which we care looking for:
As each revolution equals to 2π, the total revolution it makes before stop is
154.375 / 2π = 24.57 revolutions
Answer:
C. Horizontal component of velocity
Explanation:
Object in motion stays in motion,
nothing works against its motion in the horizontal direction, unlike in the vertical direction, gravity pulls object down.
