What would the result be of adding one proton to an atom

1 answer:

3 0

Answer:Protons carry a positive electrical charge and they alone determine the charge of the nucleus. Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number. For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium and thats your answer

Explanation:

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A 25.0 ml sample of a 0.2900 m solution of aqueous trimethylamine is titrated with a 0.3625 m solution of hcl. calculate the ph

Flauer [41]

a) After adding 10 mL of HCl

first, we need to get moles of (CH3)3N = molarity * volume

= 0.29 m * 0.025 L
= 0.00725M moles
then, we need to get moles of HCl = molarity * volume

= 0.3625 m * 0.01L
= 0.003625 moles

so moles of (CH3)3N remaining = moles of (CH3)3N - moles of HCl
= 0.00725 - 0.003625

= 0.003625 moles

and when the total volume = 0.01 L + 0.025L = 0.035 L

∴ [(CH3)3N] = moles remaining / total volume

= 0.003625 moles / 0.035L
= 0.104 M

when we have Pkb so we can get Kb :

pKb = - ㏒Kb
4.19 = -㏒Kb

∴Kb = 6.5 x 10^-5

when Kb = [(CH3)3NH+] [OH-] / [(CH3)3N]

and by using ICE table we assume we have:

[(CH3)3NH+] = X & [OH] = X

and [(CH3)3N] = 0.104 -X

by substitution:

∴ 6.5 x 10^-5 = X^2 / (0.104-X) by solving for X

∴X = 0.00257 M
∴[OH-] = X = 0.00257 M

∴POH = -㏒[OH]

= -㏒0.00257
= 2.5

∴ PH = 14 - POH
= 14 - 2.5
= 11.5
b) after adding 20ML of HCL:

moles of HCl = molarity * volume
= 0.3625 m * 0.02 L

= 0.00725 moles

the complete neutralizes of (CH3)3N we make 0.003625 moles of (CH3)3NH+ So, now we need the Ka value of (CH3)3NH+:

and when the total volume = 0.02L + 0.025 = 0.045L

∴ [ (CH3)3NH+] = moles / total volume

= 0.003625 / 0.045L
= 0.08 M

when Ka = Kw / Kb

and we have Kb = 6.5 x 10^-5 & we know that Kw = 1 x 10^-14

so, by substitution:

Ka = (1 x 10^-14) / (6.5 x 10^-5)

= 1.5 x 10^-10

when Ka expression = [(CH3)3N][H+] / [(CH3)3NH+]

by substitution:

∴ 1.5 x 10^-10 = X^2 / (0.08 - X) by solving for X

∴X = 3.5 x 10^-6 M

∴ [H+]= X = 3.5 x 10^-6 M

∴PH = -㏒[H+]

= -㏒(3.5 x 10^-6)

= 5.5

C) after adding 30ML of HCl:

moles of HCl = molarity * volume

= 0.3625m * 0.03L

= 0.011 moles

and when moles of (CH3)3N neutralized = 0.003625 moles

∴ moles of HCl remaining = moles HCl - moles (CH3)3N neutralized

= 0.011moles - 0.003625moles

= 0.007375 moles
when total volume = 0.025L + 0.03L

= 0.055L

∴[H+] = moles / total volume

= 0.007375 mol / 0.055L

= 0.134 M

∴PH = -㏒[H+]

= -㏒ 0.134

= 0.87

8 0

2 years ago

What is a Newton (N)?

hichkok12 [17]

Answer:

SI unit of force

Explanation:

Newton(N) is the Standard International unit used to measure force. This was named after Sir Isaac Newton.

HOPE THIS HELPED

3 0

2 years ago

Xenon tetrafluoride has two sets of lone pairs of electrons. What should be the relative positions of the two sets of lone pairs

Zielflug [23.3K]

Answer: Two equatorial positions so as to minimize the repulsion.

Explanation:

Formula used for calculating number of electrons :

$\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom = 8

N = number of monovalent atoms bonded to central atom = 4

C = charge of cation = 0

A = charge of anion = 0

Now we have to determine the hybridization of the $XeF_4$ molecule.

$\frac{1}{2}[8+4-0+0]=6$

Bond pair electrons = 4

Lone pair electrons = 2

The number of electrons are 6 that means the hybridization will be $sp^3d^2$ and the electronic geometry of the molecule will be octahedral.

The molecular geometry will be square planar as two alternate positio ns will be occupied by lone pair of electrons so as to minimize the repulsion.