To solve this we use the
equation,
M1V1 = M2V2
where M1 is the concentration of the stock solution, V1 is the
volume of the stock solution, M2 is the concentration of the new solution and
V2 is its volume.
2.5 M x V1 = 1.0 M x .250 L
<span>V1 = 0.10 L or 100 mL of the 2.5 M HCl solution is needed
Hope this helps.</span>
Answer: A 59.5 degree celcius
The equation that we will use to solve this problem is :
PV = nRT where:
P is the pressure of gas = 1.8 atm
V is the volume of gas = 18.2 liters
n is the number of moles of gas = 1.2 moles
R is the gas constant = 0.0821
T is the temperature required (calculated in kelvin)
Using these values to substitute in the equation, we find that:
(1.8)(18.2) = (1.2)(0.0821)(T)
T = 332.5 degree kelvin
The last step is to convert the degree kelvin into degree celcius:
T = 332.5 - 273 = 59.5 degree celcius
I only got 50 points (which is not 100). :-)
Look at the graph. At 80 °C, about 38 g of solute is able to dissolve, and that’s for ever 100 g of water. That means that for every 150 grams of water, 57 grams of solute can dissolve (38/2 = 19 + 38 = 57 g) at 80 °C. Since 57 g is greater than 55 g, all for he sodium chloride should dissolve in 150 g of water at 80 °C - you can put all of that into a “mathematical explanation”.
Answer:
C4H8
Explanation:
First find the molar mass of CH2;
2(1.01) + 1(12.01) = 14.03g
Now divide the molar mass of the compound by the molar mass of CH2;
56g/14.03g = 3.9914 Round to nearest whole number = 4
Multiply CH2 by 4 to get the molecular formula;
CH2* 4 = C4H8
