Question 4 How much time does it take to walk 8 km north at a velocity of 3.8 km/h?
1 answer:
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Answer:
10.86 N
Explanation:
Let the average frictional force acting on the toboggan be 'f' N.
Given:
Mass of toboggan (m) = 19.0 kg
Initial velocity (u) = 4.00 m/s
Final velocity (v) = 0 m/s
Time for which friction acts (Δt) = 7.00 s
Now, change in momentum is given as:
Now, we know that, change in momentum is equal to the impulse acting on the body. So,
Impulse is,
Now, we know that, impulse is also given as the product of average force and the time interval for which it acts. So,
Rewriting the above equation in terms of 'f', we get:
Plug in the given values and solve for 'f'. This gives,
Therefore, the magnitude of frictional force is
Answer:
The distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
Explanation:
Given;
speed of the faster car, v₁ = 60 mi/h
speed of the slower car, v₂ = 55 mi/h
Let the distance traveled by the faster car when it is 15 mins ahead of the slower car = x miles
Note: divide 15 mins by 60 to convert to hours for consistency in the units.
Therefore, the distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
Answer: Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).
Explanation: Impulse is defined as the force acting on an object for a short period or interval of time.
Mathematically it is given by the relation:
Impulse = Force Time
According to the numerical values given in the question, I = 202 Ns and T = 0.244 s
So, Force F = =
= 827.86 N
Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).