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Sergio [31]
3 years ago
6

Question 4 How much time does it take to walk 8 km north at a velocity of 3.8 km/h?​

Physics
1 answer:
IrinaVladis [17]3 years ago
6 0

Given parameters:

Displacement = 8km

Velocity  = 3.8km/h

Unknown:

time  = ?

Solution:

Velocity is displacement divided by time.

  Velocity  = \frac{displacement}{time}  

      Displacement  = velocity x time

Input the parameters:

              8  = 3.8  x time

 Time  = \frac{8}{3.8}   = 2.1s

The time taken is 2.1s

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What happens when a dielectric material is placed between the two charged plates of the capacitor
agasfer [191]

Answer:

Due to polarization of charges on either side the dielectric, it produces an electric field of its own which acts in a firection opposite to that of the field due to the source.

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Gases are more prone to expansion and contraction than liquid . The biggest change in the volume in your thermometer was probabl
KiRa [710]

Answer:

In the air

Explanation:

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In this problem, we are comparing water (which is a liquid) with air (which is a gas). From what we said above, this means that the change in volume is larger in the air rather than in the water.

8 0
3 years ago
A particularly beautiful note reaching your ear from a rare stradivarius violin has a wavelength of 39.1 cm. the room is slightl
raketka [301]
The wavelength of the note is \lambda = 39.1 cm = 0.391 m. Since the speed of the wave is the speed of sound, c=344 m/s, the frequency of the note is
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where \mu=0.550 g/m = 0.550 \cdot 10^{-3} kg/m is the linear mass density of our string.
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8 0
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In the Bohr model of the hydrogen atom, the electron moves in a circular orbit of radius 5.3×10−11m with a speed of 2.2×106m/s.
lisov135 [29]

Answer:

The magnitude of the electric field is 512171146711.7046 N/C.

The direction is toward the electron as electron has negative charge.

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\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

The Electric field is given by

E=\frac{e}{4\pi\epsilon_0 r^2}\\\Rightarrow B=\frac{1.6\times 10^{-19}}{4\pi\times 8.85\times 10^{-12}\times (5.3\times 10^{-11})^2}\\\Rightarrow E=512171146711.7046\ N/C

The magnitude of the electric field is 512171146711.7046 N/C.

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What is the similarity between relative dating and radioactive dating?
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