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horsena [70]
3 years ago
6

Name the carboxylic acid used to make this compound:

Chemistry
1 answer:
DiKsa [7]3 years ago
5 0

Answer:

propanoic acid is used because of the number of carbon atoms before the functional group

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Come up with a three-step plan for your household to reduce its effect on water pollution. Your plan should include a way to edu
Marina86 [1]

Answer:

1 tell your family difrent ways to safe water

2 dont leave the water running when you brush your teeth

3 dont dump cups of water out for no reason

Explanation:

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3 years ago
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A student collected a 47.5 mL sample of gas in the lab at 0.8 atm pressure and 29.00C. What volume would this gas sample occupy
Sav [38]

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the volume would be 69.034mL

Explanation:

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3 years ago
2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
The air pressure inside a submarine is 1.24 atm. What would be the height of a column of mercury (mm Hg) balanced by this pressu
Ipatiy [6.2K]
Since one atmosphere is 29.9213 inches of mercury, we can simply find this by taking 29.9213 and multiplying that by 1.24. You end up with 37.102412 inches of mercury. I hope this helps you out, and good luck on the rest of your homework.
6 0
3 years ago
Determine the correct set-up below to determine what mass, in grams, of N2 is needed to completely react with 105 g F2 ?
neonofarm [45]

Answer:

C: 1 mol F2/38 g F2

Explanation:

The reaction equation is;

N2 + 3F2 = 2NF3

Now, to know how many grams, of N2 is needed to completely react with 105 g F2 and since the molar mass of N2 is 28.02 g/mol, Molar mass of F2 is 38 g/mol, number of moles attached to N2 and F2 in the reaction are 1 and 3 moles respectively, then we will have;

105 g F2 × 1 mol F2/38 g F2 × 1 mol N2/3 mol F2 × 28.02 g N2/1 mol N2

Option C is Thus correct

4 0
3 years ago
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