Answer:
3.052 × 10^24 particles
Explanation:
To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)
The mass of Li2O given in this question is as follows: 151grams.
To convert this mass value to moles, we use;
moles = mass/molar mass
Molar mass of Li2O = 6.9(2) + 16
= 13.8 + 16
= 29.8g/mol
Mole = 151/29.8g
mole = 5.07moles
number of particles (nA) of Li2O = 5.07 × 6.02 × 10^23
= 30.52 × 10^23
= 3.052 × 10^24 particles.
Answer:
Dichloromethane
Explanation:
As we know the atomic number given belongs to following elements, i.e.
Atomic # Element M.Mass
1 Hydrogen 1 g.mol⁻¹
6 Carbon 12 g.mol⁻¹
17 Chlorine 35.5 g.mol⁻¹
Also the molecular formula of Dichloromethane is,
= CH₂Cl₂
Putting molar masses of each element,
= (12)₁ + (1)₂ + (35.5)₂
= 12 + 2 + 71
= 85 g.mol⁺¹
Result:
Hence the only possible structure containing 5 atoms is Dichloromethane.
You would have to evaporate the water to get just the sugar
Molarity = moles of solute / liters of solution
M = 0.5 / 0.05
M = 10.0 mol/L⁻¹
hope this helps!
