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nikdorinn [45]
1 year ago
6

rocky the flying squirrel is carrying a nut of mass 0.5 kg while flying horizontally at a height of 15 m above the ground at a s

peed of 12 m/s. bullwinkle is eagerly awaiting the delivery of the nut on the ground. rocky releases the nut as he is directly above bullwinkle. how far from bullwinkle will the nut land if bullwinkle does not move
Physics
1 answer:
beks73 [17]1 year ago
7 0

The nut distance from the Bullwinkle after uniform motion is 21 m.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, the parameters given are

m = 0.5 kg

s = 15 m

vx = 12 m/s

vo = 0 m/s

a = g = 9.8 m/s²

Find the time taken of the nut for landing

s = vo . t + 1/2 . a . t²

15 = 0 + 1/2 . 9.8 . t²

t² = 3.06

t = 1.75 s

Find the distance of nut in horizontal direction

vx = x / t

12 = x / 1.75

x = 12 . 1.75

x = 21 m

Find more on uniform motion at: brainly.com/question/28040370

#SPJ4

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Two concentric current loops lie in the same plane. The smaller loop has a radius of 3.8 cm and a current of 12 A . The bigger l
Stolb23 [73]

Answer:

R_2=6.33cm

Explanation:

The equation for the magnetic field at the center of a circular loop is:

B=\frac{\mu_0I}{2R}

If we name the smaller loop as 1 and the bigger loop as 2 and we impose the same magnitude of the magnetic field at their center, we have:

B_2=B_1

\frac{\mu_0I_2}{2R_2}=\frac{\mu_0I_1}{2R_1}

\frac{I_2}{R_2}=\frac{I_1}{R_1}

R_2=\frac{I_2}{I_1}R_1

Which for our values means:

R_2=\frac{I_2}{I_1}R_1=\frac{(20A)}{(12A)}(3.8cm)=6.33cm

(Notice that we don't need to convert cm to m, we get our result in cm).

3 0
3 years ago
A car moves in a straight line at a speed of 68.5 km/h. How far (in km) will the car move in 5.45 minutes at this speed?
AlekseyPX
If you divide 68.5 km/h by 60 (the minutes in an hour) and then you get 1.141 then you multiply it by 5.45 and you get 6.222!


Your Answer is 6.222!!!!
5 0
3 years ago
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nikklg [1K]

Answer:

Explanation:

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3 0
4 years ago
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Mathematically, explain how a car (A) with mass of 500 kg and velocity of 2 m/s has the same kinetic energy as a car (B) with ma
scoray [572]

Answer:

<em>Both kinetic energies are equal</em>

Explanation:

<u>Kinetic Energy </u>

Is the type of energy of an object due to its state of motion. It's proportional to the mass and the square of the speed.

The equation for the kinetic energy is:

\displaystyle K=\frac{1}{2}mv^2

Where:

m = mass of the object

v = speed of the object

The kinetic energy is expressed in Joules (J)

There are two cars:

Car (A) with mass ma=500 kg and speed va= 2 m/s

Car (B) with mass mb=20,000 gr and speed vb= 10 m/s

Calculate the kinetic energy of both cars:

\displaystyle K_a=\frac{1}{2}m_av_a^2

\displaystyle K_a=\frac{1}{2}500*2^2

\displaystyle K_a=250*4=1,000 J

To calculate the Kb, the mass must be expressed in kg:

mb=20,000/1,000 =20 Kg

\displaystyle K_b=\frac{1}{2}m_bv_b^2

\displaystyle K_b=\frac{1}{2}20*10^2

\displaystyle K_b=10*100=1,000 J

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step 2, do research
step 3, make a hypothesis
step 4, test your hypothesis with an experiment
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step 6, make a conclusion
4 0
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