Answer:
31.905 ft/s²
Explanation:
Given that
Mass of the pilot, m = 120 lb
Weight of the pilot, w = 119 lbf
Acceleration due to gravity, g = 32.05 ft/s²
Local acceleration of gravity of found by using the relation
Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)
119 = 120 * a/32. 174
119 * 32.174 = 120a
a = 3828.706 / 120
a = 31.905 ft/s²
Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²
I pretty sure that 3 is b and 4 is A and 5 I need a full picture
Kinetic energy = 1/2 m v^2 = 1/2 x1.5 x10^-3 x 0.36
Answer:
look it up im not a sheaperd sorry
Explanation:
