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2 years ago

Which of these actions would increase heat transfer between two objects?

Physics

2 answers:

sergejj [24]2 years ago

7 0

Answer:

b- increases the area of their contact

Explanation:

i did it in edge! ; )

Kaylis [27]2 years ago

3 0

Answer:

Increasing the area of their contact.

Explanation:

Just took the test and it was right.

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A 10cm long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire

soldi70 [24.7K]

Answer:

a) $v=4.0m/s$

b) $B=2.958T$

Explanation:

From the question we are told that:

Wire Length $l=10cm=>0.10m$

Resistance $R=0.35$

Force $F=1.0N$

Power $P=4.0W$

Generally the equation for Power is mathematically given by

$P=Fv$

Therefore

$v=\frac{P}{F}$

$v=\frac{4.0}{1.0}$

$v=4.0m/s$

Generally the equation for Magnetic Field is mathematically given by

$B=\frac{\sqrt{PR}}{vl}$

$B=\frac{\sqrt{4*0.35}}{4*0.10}$

$B=2.958T$

5 0

2 years ago

PLEASE HELP FOR PHYSICS!

Stolb23 [73]

Hi there!

Recall Newton's Law of Universal Gravitation:

$\large\boxed{F_g = G\frac{m_1m_2}{r^2}}$

Where:

Fg = Force of gravity (N)

G = Gravitational Constant

m1, m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the given values stated in the problem:

$F_g = (6.673*10^{-11})\frac{50 * 50}{25^2} = \boxed{2.669 * 10^{-10} N}$

8 0

2 years ago

A copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o

REY [17]

Answer:

550000000N/m

Explanation:

Given that a copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends of the wire, the wire stretches by 5.0×10−3 of its original length.

Original length L = 0.005L

the strain = extension/ original length

the strain = 0.005L / L

the strain = 0.005

Young modulus = stress / strain

11 × 10^10 = stress / 0.005

Cross multiply

Stress = 11 × 10^10 × 0.005

Stress = 550 000000 N/m

Therefore, the tensile stress on the wire is 550000000 N/m.

7 0

3 years ago

An object rotates about a fixed axis, and the angular position of a reference line on the object is given by θ = 0.220e3t, where

OLga [1]

Answer: $a_{t}=3.96$

$a_{c}=0.8712$

Explanation:

Given

$\theta =0.220e^{3t}$

r=2cm

Now angular velocity is given by $\omega =\frac{\mathrm{d}\theta}{\mathrm{d}t}$

$\omega =0.66e^{3t}$

Now linear velocity(v) is given = $\omega r$

$v=1.32e^{3t}$

Now tangential component of acceleration is given by

$a_{t}=\frac{\mathrm{d}\vec{v}}{\mathrm{d}t}=3.96e^{3t}$

at t=0

$a_{t}=3.96cm/s^2$

radial component of acceleration is given by

$a_{c}=\omega ^{2}r$

$a_{c}=0.4356e^{6t}\times 2$

$a_{c}=0.8712e^{6t} cm/s^{2}$

at t=0

$a_c=0.8712 cm/s^{2}$

5 0

3 years ago

What determines the amount of energy a substance has

Aleks04 [339]

If you think more specifically about energy,such as thermal energy,the amount of that energy a substance has is determined by the movement of the molecules.hope this helps u

3 0

3 years ago