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Masja [62]
1 year ago
11

SolveV minus 10 equal -9

Mathematics
1 answer:
babymother [125]1 year ago
8 0

v-10=-9

Solve for v.

Add 10 to each side of the equation:

v-10+10 =-9+10

v= 1

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Please help me with this question
Vladimir [108]

Answer: 20

Step-by-step explanation:

numbers belonging to the figure on the left are 2.5 times less than on the right so to find x multiply 8 by 2.5 and that is 20

7 0
3 years ago
(x+16)²=12 plz help me and show work
Readme [11.4K]

Answer:

The answer is x=-16 ±2\sqrt{3} in exact form or x=-12.535898, x=-19.464102 in decimal form.

Step-by-step explanation:

To solve this problem, start by moving all terms to the left side of the equation and simplify. Simplify the equation by subtracting 12 from both sides of the equation and squaring x+16, which will look like x^{2} +32x+256-12=0. Next, simplify the equation again, which will look like x^{2} +32x+244=0.

Then, use the quadratic formula to find the solutions. The quadratic formula looks like\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a}.

For this problem, the quadratic variables are as follows:

a=1

b=32

c=244

The next step is to substitute the values a=1, b=32, and c=244 into the quadratic formula and solve. The quadratic formula will look like \frac{-32(+-)\sqrt{32^2-4(1*244)} }{2*1}. To simplify the equation, start by simplifying the numerator, which will look like x=\frac{-32(+-)4\sqrt{3} }{2*1}. Then, multiply 2 by 1 and simplify the equation, which will look like x=-16(+-)2\sqrt{3}. The final answer is x=-16 ±2\sqrt{3} in exact form. In decimal form, the final answer is x=-12.535898, x=-19.464102.  

6 0
3 years ago
What is the domain and derivative of f(x)=ln(2xsqrt(2+x))?
wolverine [178]
For domain 2x sqrt(2+x)>0
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f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
5 0
3 years ago
Which one of the following tables is a relation that represents a function?
TiliK225 [7]
C is the correct answer homie
4 0
3 years ago
Read 2 more answers
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Ghella [55]

Answer:

The ladder reach a height 8.485 ft.

Step-by-step explanation:

The ladder with the building made right angle triangle

The length of the ladder is the hypotenuse 12 ft.

The angle between the ladder and the building is 45°

The height of the ladder reach is the vertical side of the Δ

∴ h = 12 cos 45° = 6√2 = 8.485 ft.

4 0
3 years ago
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