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posledela
1 year ago
6

A specific amount of energy is emitted when excited electrons in an atom in a sample of an element return to the ground state. T

his emitted energy can be used to determine the.
Physics
1 answer:
Flauer [41]1 year ago
6 0

Answer:

C. identity of the element

The specific amount of energy emitted when electrons jump from excited states to the ground state refers to emission spectrum. The energy is emitted in the form of photons, and the photons have very specific wavelengths (energy) that correspond to the energy gaps between the excited states and the ground state. The specific wavelengths of light emitted are referred to as the "emission spectrum," and each element produces a different emission spectrum. Thus, this emitted energy can be used to identify the element from which your sample was taken.

Explanation:

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KatRina [158]

Answer:

i would think the first two, but i cant be sure.

Explanation:

7 0
4 years ago
If a snowboarder’s initial speed is 4 m/s and comes to rest when making it to the upper level. With a slightly greater initial s
Brrunno [24]

(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

<h3>Conservation of mechanical energy</h3>

The effect of height  and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;

ΔK.E = ΔP.E

¹/₂m(v²- u²) = mg(hi - hf)

¹/₂(v²- u²) = g(0 - hf)

v² - u² = -2ghf

v² = u² - 2ghf

where;

  • v is the final velocity at upper level
  • u is the initial velocity
  • hf is final height
  • g is acceleration due to gravity

when u² = 2gh, then v² = 0,

when gravity reduces, u² > 2gh, and v² > 0

Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

<h3>Final speed</h3>

v² = u² - 2ghf

where;

  • u is the initial speed = 5 m/s
  • g is acceleration due to gravity and its less than 9.8 m/s²
  • v is final speed
  • hf is equal height

Since g on Epislon is less than 9.8 m/s² of Earth;

5² - 2ghf > 3 m/s

Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

Learn more about conservation of mechanical energy here: brainly.com/question/6852965

5 0
3 years ago
Here is a force diagram of an object in water. The weight of the object is 15N and the buoyancy force is 17N. Will the object fl
lawyer [7]

Answer:

Object will float.

Explanation:

Total force on the body = Weight of body + Buoyancy force on body.

 Weight of body = 15 N downwards = 15 N

 Buoyancy force on body = 17 N upwards = -17 N

 Total force on body = 15 - 17 = -2 N = 2 N upwards

 So, the body will float.

Object will float.

8 0
3 years ago
5. 3 women push a stalled car. Each woman pushes with a 400N force. What is the mass of the car if the car accelerates at 0.85 m
iris [78.8K]

Answer:

<h2>470.59 kg</h2>

Explanation:

The the mass of the car can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{400}{0.85}  \\  = 470.58823...

We have the final answer as

<h3>470.59 kg</h3>

Hope this helps you

7 0
3 years ago
A basketball has a mass of 567 g. Heading straight downward, in the direction, it hits the floor with a speed of 2 m/s and rebou
Vsevolod [243]

Answer:

\Delta p=2.27\frac{kg\cdot m}{s}

Explanation:

The momentum change is defined as:

\Delta p=p_f-p_i\\\Delta p=mv_f-mv_i\\\Delta p=m(v_f-v_i)(1)

Taking the downward motion as negative and the upward motion as positive, we have:

v_f=2\frac{m}{s}(2)\\v_i=-2\frac{m}{s}(3)

Replacing (2) and (3) in (1):

\Delta p=567*10^{-3}kg(2\frac{m}{s}-(-2\frac{m}{s}))\\\Delta p=2.27\frac{kg\cdot m}{s}

5 0
3 years ago
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