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jenyasd209 [6]
2 years ago
8

Light from two lasers is incident on an opaque barrier with a single slit of width 4.0 x 10^-4 m. One laser emits light of wavel

ength 480 nm and the other is 640 nm. A screen to view the light intensity pattern is 2.0 m behind the barrier. The distance from the center of the pattern to the nearest completely dark spot (dark for both colors) is ____ cm. (include 2 digits after the decimal point)
Physics
1 answer:
Sergio [31]2 years ago
7 0

Answer:

a) y = 2.4 x 10⁻³ m = 0.24 cm

b) y = 3.2 x 10⁻³ m = 0.32 cm

Explanation:

The formula of Young's Double Slit experiment will be used here:

y = \frac{\lambda L}{d}\\\\

where,

y = distance between dark spots = ?

λ = wavelength

L = distance of screen = 2 m

d = slit width = 4 x 10⁻⁴ m

a) FOR λ = 480 nm = 4.8 x 10⁻⁷ m:

y = \frac{(4.8\ x\ 10^{-7}\ m)(2\ m)}{4\ x\ 10^{-4}\ m}

<u>y = 2.4 x 10⁻³ m = 0.24 cm</u>

<u></u>

a) FOR λ = 640 nm = 6.4 x 10⁻⁷ m:

y = \frac{(6.4\ x\ 10^{-7}\ m)(2\ m)}{4\ x\ 10^{-4}\ m}

<u>y = 3.2 x 10⁻³ m = 0.32 cm</u>

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Ymorist [56]

This question is incomplete the complete question is

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Answer:

(a) Xs=0.459m

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Explanation:

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(b) For Time

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For T1

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For T2

x_{l}=Vbt+(1/2)gt_{2}^{2}\\   as\\x_{l}=x_{1}+x_{s}\\x_{l}=1.8+0.459\\x_{l}=2.259\\so\\t_{2}=\frac{2.259*2}{9.8} \\t_{2}=0.6789s

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(c) To find Vc

Vc=Vb+gt2

Vc=(0)+(9.8)(0.6789)

Vc=6.65 m/s

7 0
3 years ago
A motorcycle and a police car are moving toward one another. The police car emits sound with a frequency of 523 Hz and has a spe
Firdavs [7]

To solve this problem it is necessary to apply the concepts related to Dopler's Law. Dopler describes the change in frequency of a wave in relation to that of an observer who is in motion relative to the Source of the Wave.

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c = Propagation speed of waves in the medium

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v_s= Speed of the source relative to the medium

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The sign depends on whether the receiver or the source approach or move away from each other.

Our values are given by,

v_s = 32.2m/s \rightarrow Velocity of car

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Replacing we have that

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3 years ago
The velocity of particle varies with time as equation
Advocard [28]

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2 years ago
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navik [9.2K]

Answer:

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In the unit conversion, the size of the object is not changed, only the value with respect to which it is measured is changed, for this reason in the conversion the amount that is in parentheses must be worth one.

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Unfortunately, it is not clearly indicated what measure it is, but the most used unit in physics is   m / s² , which is a measure of acceleration. Let's cut this down

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3 years ago
A sound wave traveling at 340 m/s is generated by a 480 Hz tuning fork.
Shtirlitz [24]

Answer:

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