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g100num [7]
1 year ago
10

Can you find the error? MgOH2

Chemistry
1 answer:
Ira Lisetskai [31]1 year ago
6 0

The error is in the formula is bracket so the correct is Mg(OH)₂

The incorrect or error in the formula is bracket that would be that the compound contain only 1Mg atom and 1 oxygen atom and 2 hydrogen atom but is wrong when you write it in an electron dot diagram you will see that it is wrong there be unshared paired of electron and the correct formula is Mg(OH)₂

Know more about Mg(OH)₂

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Sodium metal and water react to form hydrogen and sodium hydroxide. If 1.99 g of sodium react with water to form 0.087 g of hydr
zavuch27 [327]

Answer:

1.56 g of water was involved in the reaction

Explanation:

From the stoichiometric equation

2Na + 2H2O = 2NaOH + H2

NB : Mm Na= 23, Mm H2O = ( 2+16)= 18

2(23) of Na requires 2(18) of water

Hence 1.99g of Na will require 1.99×2×18/2(23) of water = 1.56 g of water

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3 years ago
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7 0
3 years ago
0.0278, how many significant figures
My name is Ann [436]

Answer:

There are three significant figures

Explanation:

When counting sig figs you don't count the zeros unless it is between a number greater than zero. The two zeros aren't between the greater numbers so there are only 3.

3 0
2 years ago
When hydrogen sulfide gas is bubbled into a solution of sodium hydroxide, the reaction forms sodium sulfide and water. How many
Mumz [18]

Answer:

1.61 g Na₂S

Explanation:

To find the mass of sodium sulfide (Na₂S) generated from hydrogen sulfide (H₂S) and sodium hydroxide (NaOH), you need to (1) construct the balanced chemical equation, then (2) calculate the molar masses of each molecule involved, then (3) convert grams of each reagent to grams of the product (via the molar masses and mole-to-mole ratio from equation coefficients), and then (4) determine the limiting reagent and final answer. It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).

(Step 1)

The unbalanced equation:

H₂S + NaOH ---> Na₂S + H₂O

Reactants: 3 hydrogen, 1 sulfur, 1 sodium, 1 oxygen

Products: 2 hydrogen, 1 sulfur, 2 sodium, 1 oxygen

The balanced equation:

H₂S + 2 NaOH ---> Na₂S + 2 H₂O

Reactants: 4 hydrogen, 1 sulfur, 2 sodium 2 oxygen

Products: 4 hydrogen, 1 sulfur, 2 sodium, 4 oxygen

(Step 2)

Molar Mass (H₂S): 2(1.008 g/mol) + 32.065 g/mol

<u>Molar Mass (H₂S)</u>: 34.081 g/mol

Molar Mass (NaOH): 22.990 g/mol + 15.998 g/mol + 1.008 g/mol

<u>Molar Mass (NaOH)</u>: 39.998 g/mol

Molar Mass (Na₂S): 2(22.990 g/mol) + 32.065 g/mol

<u>Molar Mass (Na₂S)</u>: 78.045 g/mol

(Step 3)

1.50 g H₂S          1 mole            1 mole Na₂S          78.045 g
-----------------  x  ----------------  x  --------------------  x  -----------------  =
                           34.081 g          1 mole H₂S            1 mole

=  3.43 g Na₂S

1.65 g NaOH           1 mole              1 mole Na₂S          78.045 g
--------------------  x  ----------------  x  -----------------------  x  ----------------  =
                              39.998 g        2 moles NaOH          1 mole

=  1.61 g Na₂S

(Step 4)

Because NaOH generates less product, it will run out before all of the H₂S is used. This makes NaOH the limiting reagent and the final answer 1.61 grams Na₂S.

5 0
1 year ago
Which of the following is a nonrenewable resource?
dybincka [34]

C. Natural gas

Hope this helps!

8 0
3 years ago
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