Answer:
The answer to your question is    V = 0.32 L
Explanation:
Data
Volume of NH₃ = ?
P = 3.2 atm
T = 23°C
mass of CaH₂ = 2.65 g
Balanced chemical reaction
                6Ca  +  2NH₃   ⇒   3CaH₂  +  Ca₃N₂
Process
1.- Convert the mass of CaH₂ to moles
-Calculate the molar mass of CaH₂
  CaH₂ = 40 + 2 = 42 g
                              42 g ------------------ 1 mol
                               2.65 g --------------  x
                               x = (2.65 x 1)/42
                               x = 0.063 moles
2.- Calculate the moles of NH₃
                      2 moles of NH₃ --------------- 3 moles of CaH₂
                       x                        --------------- 0.063 moles
                                 x = (0.063 x 2) / 3
                                 x = 0.042 moles of NH₃
3.- Convert the °C to °K
Temperature = 23°C + 273
                       = 296°K
4.- Calculate the volume of NH₃
-Use the ideal gas law 
               PV = nRT
-Solve for V
                 V = nRT / P
-Substitution
                 V = (0.042)(0.082)(296) / 3.2
-Simplification
                V = 1.019 / 3.2
-Result
                V = 0.32 L
 
        
             
        
        
        
Between 23 and 87%
Sorry if I’m wrong
        
             
        
        
        
Answer: When two light bulbs are connected in parallel, which is true? A. The total resistance is less than the resistance of either bulb alone. B. The Voltage provided 
Explanation:
 
        
             
        
        
        
Answer:
When a front passes over an area, it means a change in the weather. Many fronts cause weather events such as rain, thunderstorms, gusty winds, and tornadoes. At a cold front, there may be dramatic thunderstorms. At a warm front, there may be low stratus clouds. Usually, the skies clear once the front has passed.
Explanation:
Plz make me brainliest :)
Have a nice day
 
        
                    
             
        
        
        
Answer:
35.75 days
Explanation:
From the given information:
For first-order kinetics, the rate law can be expressed as:

Given that:
the rate degradation constant = 0.12 / day
current concentration C = 0.05 mg/L
initial concentration C₀ = 3.65 mg/L

㏑(0.01369863014) = -(0.12) t
-4.29 = -(0.12)
t = -4.29/-0.12
t = 35.75 days