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9966 [12]
3 years ago
11

Which item is made from a synthetic material?

Chemistry
2 answers:
miss Akunina [59]3 years ago
8 0

Answer: Option (a) is the correct answer.

Explanation:

A synthetic material is an artificial material and they are not obtained naturally.

We can also say that synthetic material are man-made. For example, nylon, rayon, acrylic etc.

Leather jackets are made up of animal skin. Hence, they are not synthetic material. Paper is obtained from plants and hence, it is not man-made. Wicker basket is made from material obtained from plants or trees. Therefore, wicker basket is not man-made.

Thus, we can conclude that out of the given options cotton pants is made from a synthetic material.

seropon [69]3 years ago
7 0
First one because Common synthetic materials are nylon, acrylic, polyester, carbon fiber, rayon and spandex. Synthetic materials are made from chemicals and are usually based on polymers. They are stronger than natural and regenerated materials.
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Study the reaction. NO(g) ⇌ 12N2(g) + 12O2(g) ΔH = −90.3 kJ Which statement about the reaction is correct? A) The reverse reacti
lozanna [386]

Answer:

The forward reaction is an exothermic reaction.

Explanation:

An exothermic reaction is one in which energy is released, usually in the form of heat hence the enthalpy of the reaction is negative. When a reaction exothermic, the energy of the reactants is greater than the energy of the products hence the excess energy is given out as heat. The reactants lie at a higher energy level in the reaction profile compared to the products.

When we look at the reaction given in the question, NO(g) ⇌ 12N2(g) + 12O2(g) ΔH = −90.3 kJ , we can easily see from the thermochemical reaction that the forward reaction is exothermic, energy is released by the reaction system as evidenced by the negative enthalpy of reaction.

4 0
3 years ago
Calculate the pH of a 1.00 L buffer of 0.97 M CH3COONa / 1.02 M CH3COOH before and after the addition of the following species.
ivanzaharov [21]

Answer:

a) 4.73

b) 4.78

c) 4.66 (further addition)  or 4.60 (starting from the original buffer solution)

Explanation:

<u>Step 1:</u> Data given

volume of the buffer = 1.00 L

Buffer = 0.97 M CH3COONa / 1.02 M CH3COOH

pKa CH3COOH = 4.75

<u>Step 2: </u>pH = pKa + log [CH3COONa]/[CH3COOH]

pH = 4.75 + log (0.97/1.02)

pH =<u> 4.73</u>

(b) pH after addition of 0.065 mol NaOH

Adding 0.065 mol NaOH will reduce the acid by that amount leaving 1.02 - 0.065 = 0.955 moles HA in 1 L so [HA] = 0.955; the neutralized acid produces A- in the same amount, increasing [A-] to 0.97 +0.065 = 1.035

pH = pKa + log[CH3COONa]/[CH3COOH]

pH = 4.75 + log(1.035/0.955)

pH = <u>4.78</u>

c) pH after<u> further</u> addition of 0.144 mol HCl

The reverse will happen after the addition of HCl:

[HA] = 0.955 + 0.144 = 1.099

[A-] = 1.035 - 0.144 = 0.891

pH = 4.75 + log(0.891/1.099)

pH = 4.66

If we add 0.144 mol of HCl to the original buffer we will get:

[HA] = 1.02 + 0.144 = 1.164

[A-] = 0.97 - 0.144 = 0.826

pH = 4.75 + log(0.826/1.164)

pH = 4.60

3 0
3 years ago
A 0.130 mole quantity of NiCl 2 is added to a liter of 1.20 M NH 3 solution. What is the concentration of Ni 2 + ions at equilib
rosijanka [135]

This is an incomplete question, here is a complete question.

A 0.130 mole quantity of NiCl₂ is added to a liter of 1.20 M NH₃ solution. What is the concentration of Ni²⁺ ions at equilibrium? Assume the formation constant of Ni(NH₃)₆²⁺ is 5.5 × 10⁸

Answer : The concentration of Ni^{2+} ions at equilibrium is, 4.31\times 10^{-8}

Explanation :  Given,

Moles of NiCl_2 = 0.130 mol

Volume of solution = 1 L

Concentration=\frac{Moles }{Volume}

Concentration of NiCl_2 = Concentration of Ni^{2+} = 0.130 M

Concentration of NH_3 = 1.20 M

K_f=5.5\times 10^8

The equilibrium reaction will be:

                      Ni^{2+}(aq)+6NH_3(aq)\rightarrow [Ni(NH_3)_6]^{2+}

Initial conc.    0.130       1.20                     0

At eqm.             x       [1.20-6(0.130)]      0.130

                                   = 0.42

The expression for equilibrium constant is:

K_f=\frac{[Ni(NH_3)_6^{2+}]}{[Ni^{2+}][NH_3]^6}

Now put all the given values in this expression, we get:

5.5\times 10^8=\frac{(0.130)}{(x)\times (0.42)^6}

x=4.31\times 10^{-8}

Thus, the concentration of Ni^{2+} ions at equilibrium is, 4.31\times 10^{-8}

7 0
4 years ago
How much energy is required to boil 65 grams of 100°C water<br> And then heat the steam to 150°C?
Artyom0805 [142]

Answer:

13598 J

Explanation:

Q = m × c × ∆T

Where;

Q = amount of energy (J)

m = mass (grams)

c = specific heat capacity

∆T = change in temperature

m = 65g, specific heat capacity of water = 4.184J/g°C, initial temperature= 100°C, final temperature = 150°C

Q = 65 × 4.184 × (150 - 100)

Q = 271.96 × 50

Q = 13598 J

Hence, 13598 J of energy is required to boil 65 grams of 100°C water and then heat the steam to 150°C.

8 0
3 years ago
Pick any habitat and model a food web to illustrate the flow of food energy. Those were your teacher’s instructions. You created
Dafna11 [192]

It's not a food web it's a food chain. I just did the exam a few minutes ago. Please mark it Brainliest.

5 0
3 years ago
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