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1 year ago

2KI → 2

Physics

1 answer:

iogann1982 [59]1 year ago

4 0

The chemical symbol used is 2K + 2I to complete the equation for the decomposition reaction.

<h3>What is decomposition reaction?</h3>

Decomposition reaction is defined as a chemical reaction when the reactant or molecule breaks down into less complex compounds Consequently, when a single reactant splits into two or more products. Because two or more reactants are combined to create a single product in a combination reaction, they are known as the opposite of a combination reaction.

One reactant produces two or more products during a decomposition process. Iodine and potassium will be produced as potassium iodide breaks down. With two K and two I on each side, this equation is balanced. It can be described using the all-inclusive formula: AB --> A + B.

Thus, the chemical symbol used is 2K + 2I to complete the equation for the decomposition reaction.

To learn more about decomposition reaction, refer to the link below:

brainly.com/question/8009068

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Air at 3 104 kg/s and 27 C enters a rectangular duct that is 1m long and 4mm 16 mm on a side. A uniform heat flux of 600 W/m2 is

ad-work [718]

Answer:

$T_{out}=27.0000077$ ºC

Explanation:

First, let's write the energy balance over the duct:

$H_{out}=H_{in}+Q$

It says that the energy that goes out from the duct (which is in enthalpy of the mass flow) must be equals to the energy that enters in the same way plus the heat that is added to the air. Decompose the enthalpies to the mass flow and specific enthalpies:

$m*h_{out}=m*h_{in}+Q\\m*(h_{out}-h_{in})=Q$

The enthalpy change can be calculated as Cp multiplied by the difference of temperature because it is supposed that the pressure drop is not significant.

$m*Cp(T_{out}-T_{in})=Q$

So, let's isolate $T_{out}$ :

$T_{out}-T_{in}=\frac{Q}{m*Cp}\\T_{out}=T_{in}+\frac{Q}{m*Cp}$

The Cp of the air at 27ºC is 1007 $\frac{J}{kgK}$ (Taken from Keenan, Chao, Keyes, “Gas Tables”, Wiley, 1985.); and the only two unknown are $T_{out}$ and Q.

Q can be found knowing that the heat flux is 600W/m2, which is a rate of heat to transfer area; so if we know the transfer area, we could know the heat added.

The heat transfer area is the inner surface area of the duct, which can be found as the perimeter of the cross section multiplied by the length of the duct:

Perimeter:

$P=2*H+2*A=2*0.004m+2*0.016m=0.04m$

Surface area:

$A=P*L=0.04m*1m=0.04m^2$

Then, the heat Q is:

$600\frac{W}{m^2} *0.04m^2=24W$

Finally, find the exit temperature:

$T_{out}=T_{in}+\frac{Q}{m*Cp}\\T_{out}=27+\frac{24W}{3104\frac{kg}{s} *1007\frac{J}{kgK} }\\T_{out}=27.0000077$

$T_{out}$ =27.0000077 ºC

The temperature change so little because:

The mass flow is so big compared to the heat flux.
The transfer area is so little, a bigger length would be required.

3 0

3 years ago

Find the distance traveled in one back-and-forth swing by the weight of a 12 in. Pendulum that swings through a 75 degree angle.

tia_tia [17]

The distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

The period of pendulum can be calculated by

$T = 2\pi \sqrt {\dfrac Lg}$

Where,

$T$ - period

$L$ - length = 12 inches

$g$ - gravitational acceleration = $\bold {9.8\rm \ m/s^2}$

Put the values,

$T = 2\pi \sqrt {\dfrac {12}{9.8}}\\\\T = 2 \times 3.14 \times \sqrt {0.122}\\\\T = 2.191$

Now, the angular displacement of the pendulum can be calculated by,

$\theta = A\times\rm \ cos(\omega T)$

Where,

$A$ - amplitude

$\theta$ - angle = $75^o$

$\omega$ - angular displacement = $2\pi/T$ = 2.866 m

Put the values and calculate for $\omega$ ,

$75 = A\times{\rm \ cos}(2.866\times 2.191)\\\\75 =A \times cos\ 6.26\\\\A =\dfrac {75}{0.99}\\\\A = 75.75 \rm \ inches$

Therefore, the distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

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3 years ago

A seesaw pivots as shown in below. What is the net torque about the pivot point?

rodikova [14]

Answer:

2.3 Nm clockwise

Explanation:

Take counterclockwise to be positive and clockwise to be negative.

∑τ = (3 N) (2.5 m) − (7 N) (1.4 m)

∑τ = 7.5 Nm − 9.8 Nm

∑τ = -2.3 Nm

The net torque is 2.3 Nm clockwise.

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4 years ago

The current in a wire is 4.00A. How much time is needed for 1 mole of electrons (6.02×1023 electrons) to pass a point in the wir

scZoUnD [109]

Answer:

t= 24080 s

Explanation:

Given that

Current in the wire ,I = 4 A

The charge ,q = 6.02 x 10²³ e C

We know that

$I=\dfrac{q}{t}$

I=Current

q=Charge

t=time

$t=\dfrac{q}{I}$

Now by putting the values in the above equation we get'

$t=\dfrac{6.02\times 10^{23}\times 1.6\times 10^{-19}}{4}\ s$

t= 24080 s

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3 years ago

The atmosphere of Jupiter is essentially made up of hydrogen, H2. For H2, the specific gas constant is 4157 J/(kg K). The accele

Alenkinab [10]

Answer:

h=17357.9m

Explanation:

The atmospheric pressure is just related to the weight of an arbitrary column of gas in the atmosphere above a given area. So, if you are higher in the atmosphere less gass will be over you, which means you are bearing less gas and the pressure is less.

To calculate this, you need to use the barometric formula:

$P=P_0e^{-\frac{Mg}{RT}h}$