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Explanation:
How much thermal energy is released when 500g of steam at 100° C condenses into water and cools to 50°C
Givens: m=0.5 kg
t = 50
c = 2.010
Qtotal = Q1 + Q2
Qtotal = QmcΔt + mLv
Qtotal = (0.5kg)(2.010)(50) + (0.5)(2.3*10^6)
Qtotal = 1.15 * 10^6
The book says that the answer is 1.3*10^6?
What did I do wrong here?
Answer:
a ) 4.5 N.s
b) V =5 m/s
Explanation:
given,
mass of rifle(M) = 0.9 kg
mass of bullet(m) = 6 g = 0.006 kg
velocity of the bullet(v) = 750 m/s
a) momentum of bullet = m × v
= 750 × 0.006
= 4.5 N.s
b) recoil velocity
m × u + M × U = m × v + M × V
0 + 0 = 0.006 × 750 - 0.9 × V
V =
V =5 m/s
This is reactivity. It describes how easily one substance reacts with another
Answer:
Correct answer: V = 18.43 m/s
Explanation:
Let be initial velocity (speed) V₀ and the current speed at some point V
At start, the box had kinetic energy which is equal to the total energy.
Ek₁ = E = m v₀²/2 = 40 · 20²/2 = 8,000 J
At the ramp point 3m high the box had potential energy:
Ep = m · g · h = 40 · 10 · 3 = 1,200 J we took that g= 10 m/s²
The total energy at any time is equal :
E = Ek + Ep ⇒ Ek = E - Ep = 8,000 - 1,200 = 6,800 J
Ek = m V²/2 ⇒ V = √2 · Ek/m = √ 2 · 6,800/40 = √340 = 18.43 m/s
V = 18.43 m/s
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