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1 year ago

What are the spectator ions in the reaction between mg(oh)2 (aq) and hcl (aq)?

Chemistry

1 answer:

vivado [14]1 year ago

6 0

The spectator ions in the reaction between aqueous $Mg(OH)_2$ and aqueous HCl would be $Mg^{2+$ and $Cl^-$ ions.

<h3>What are spectator ions?</h3>

Spectator ions are anions or cations that exist both as reactants and as products in a reaction. Their forms remain unchanged both in the reactants and in the products.

Aqueous $Mg(OH)_2$ and aqueous HCl react according to the following equation:

$Mg (OH)_2 (aq) + 2HCl (aq) --- > MgCl_2 (aq) +2 H_2O (l)$

Before the reaction, $Mg^{2+$ and $Cl^-$ existed in the reactants as $Mg(OH)_2$ and HCl respectively. After the reaction, $Mg^{2+$ and $Cl^-$ exist as $MgCl_2$ in the product.

Thus, the spectator ions in this case are $Mg^{2+$ and $Cl^-$ ions because their forms did not change after the reaction.

More on spectator ions can be found here: brainly.com/question/28913274

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lutik1710 [3]

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Reason:
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How are saturated and supersaturated solutions similar?

Serggg [28]

Answer:

They are similar in sense that both cannot dissolve any more solid unless heat or other factors are added. For eg if a solution is saturated it can no longer dissolve the given substance. But if the solution is heated, the solid will dissolved this is now said to be supersaturated.

Explanation:

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3 years ago

I need help on this ASAP

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3 years ago

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Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an

garri49 [273]

Explanation:

The given data is as follows.

T = $120^{o}C$ = (120 + 273.15)K = 393.15 K,

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So, $x_{1}$ = 0.5 and $x_{2}$ = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

$p^{sat}_{1}$ (393.15 K) = 9.2 bar

$p^{sat}_{1}$ (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

$p_{1} = x_{1} \times p^{sat}_{1}$

= $0.5 \times 9.2 bar$

= 4.6 bar

and, $p_{2} = x_{2} \times p^{sat}_{2}$

= $0.5 \times 10.5 bar$

= 5.25 bar

Therefore, the bubble pressure will be as follows.

P = $p_{1} + p_{2}$

= 4.6 bar + 5.25 bar

= 9.85 bar

Now, we will calculate the vapor composition as follows.

$y_{1} = \frac{p_{1}}{p}$

= $\frac{4.6}{9.85}$

= 0.467

and, $y_{2} = \frac{p_{2}}{p}$

= $\frac{5.25}{9.85}$

= 0.527

Calculate the dew point as follows.

$y_{1}$ = 0.5, $y_{2}$ = 0.5

$\frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}$

$\frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}$

$\frac{1}{P}$ = 0.101966 $bar^{-1}$

P = 9.807

Composition of the liquid phase is $x_{i}$ and its formula is as follows.

$x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}$

= $\frac{0.5 \times 9.807}{9.2}$

= 0.5329

$x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}$

= $\frac{0.5 \times 9.807}{10.5}$

= 0.467

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3 years ago

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erastova [34]

Answer:

B. Atom, molecule, cell, organism

Explanation:

Atoms make up molecules. Molecules make up cells. Cells make up tissue. A number of tissues working together creates an organ. Multiple organs working together creates an organ system. Organ systems working together creates one happy, functioning organism. :)

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