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natta225 [31]
3 years ago
12

Graphite, an allotrope of carbon, is converted into cubic diamond through a process that may take a billion years or longer.

Chemistry
1 answer:
andriy [413]3 years ago
5 0

Answer:

The given statement is true.

Explanation:

The given statement is true.

As per an estimate, to convert graphite into diamond nearly 1 billion to 3.3 billion years of time is required.

Graphite converts into diamond when high-pressure is applied deep in the earth core.

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A fusion reaction takes place between carbon and another element neutrons are released and a different element is formed the dif
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A fusion reaction takes place between carbon and another element. Neutrons are released, and a different element is formed. The different element is Lighter than helium.

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What is the molar mass of PCL3
antiseptic1488 [7]
The molar mass for PCL3 is 137.33 g/mol
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Identify the blocks and groups of elements in the periodic table​
djyliett [7]

Explanation:

The periodic table is a table that arranges elements based on their atomic numbers into groups and periods.

The groups are the vertical arrangement of elements. All elements in a group share similar chemical properties because they have the same number of elements in their valence shell. The periodic table groups are:

               Group                             Other names

              1A or 1                               Alkali metals

              IIA or 2                              Alkaline earth metals

             IIIA or 3                            Boron family

             VIA or 6                             Chalcogens

            VIIA or 17                            Halogens

             O-18                                  Inert elements

             IIIB-IIB                              Transition elements

There are 18 vertical columns divided into 8 tall groups or main groups which are 1A to O. The short groups or subgroups are from numerals 1B to VIII.

The periodic table can be divided into four blocks based on the type of sublevels their valence electrons occupy.

  • Group IA and IIA constitute the s-block
  • Group IIIA to O constitute the p-block
  • The transition elements makes up the d-block
  • The lanthanides and actinides makes up the f-block

Learn more:

Periodic table brainly.com/question/2014634

#learnwithBrainly

3 0
3 years ago
What's the difference between gold and other metals
Zanzabum
Well, gold is way different form other say for instance what if you get a really good ring not to expensive or cheap, but its in between those characteristics what if u get a gold ring to compare now one might tarnish or fade, but if you really look at it that gold one will not it really all dependents on what metals your talking about cause all metals aren't the same some fade and some don't . Also the oxygen level is weak for other metals, but gold it different it can still keeps its shine .

 - That's the best explanation i can give IF ITS NOT ENUH OR NOT RIGHT JUH COMMENT BELOWW↓↓ I WILL THINK OF SOMEThING ELSE THANKS! YOU HAVE A GREAT DAYY .
5 0
3 years ago
5.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the
cupoosta [38]

Answer: Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

Explanation:

To calculate the entalpy, we use the equation:

q=mc\Delta T

where,

q = heat absorbed by water = ?

m = mass of water = {\text {volume of water}}\times {\text {density of water}}=100.0ml\times 1.00g/ml=100.0g

c = heat capacity of water = 4.186 J/g°C

\Delta T= change in temperature = 6.70^0C

q=100.0g\times 4.184J/g^0C\times 6.70^0C=2803.3J=2.8033kJ

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

The heat absorbed by water will be equal to heat released by MgSO_4

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 5.11 g

Molar mass  = 120 g/mol

Putting values in above equation, we get:

\text{Moles of }MgSO_4=\frac{5.11g}{120g/mol}=0.042mol

0.042 moles of MgSO_4 releases = 2.8033 kJ

1 mole of MgSO_4 releases = \frac{2.8033 kJ}{0.042}\times 1=66.7kJ

Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

3 0
3 years ago
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