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1 year ago

Is this the right answer to this question....?

1 answer:

3 0

Transport of Na+ from a place of low concentration to a place of higher concentration. <u>This is the right answer.</u>

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The sodium-potassium pump is the most common and well-known example of active transport. At the cell membrane, the sodium-potassium pump moves 3 sodium ions out of the cell and two potassium ions into the cell per ATP. Examples of active transport include the uptake of glucose in the human intestine and the uptake of minerals and ions into the root hair cells of plants.

One of the greatest examples of active transport is the movement of calcium ions out of cardiomyocytes. Cells secrete proteins such as enzymes, antibodies, and various other peptide hormones. Amino acids are transported across the intestinal mucosa of the human intestine. The movement of ions or molecules across cell membranes to regions of a higher concentration is assisted by enzymes and requires energy.

Learn more about Active transport here:-brainly.com/question/25802833

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Write the chemical equation for ionic reaction between nabr and agno3. b boldi italicsu underline bulleted list numbered list su

evablogger [386]

Step 1; write the molecular equation, that is
NaBr(aq) +AgNO3 (aq)---> AgBr(s) +NaNO3 the equation is balanced
ionic equation is therefore
Na+(Aq) +Br- (aq) + Ag+(aq) + No3-(aq) --->AgBr(s) +Na+(aq) + No3-(aq)

net equation
Ag+(aq) +Br-(aq) --->AgBr(s)

7 0

3 years ago

Fe(s) + CuSO4(aq) <===> Cu(s) + FeSO4(aq)

Ludmilka [50]

Answer : The original concentration of copper (II) sulfate in the sample is, $5.6\times 10^{-1}g/L$

Explanation :

Molar mass of Cu = 63.5 g/mol

First we have to calculate the number of moles of Cu.

Number of moles of Cu = $\frac{\text{Mass of Cu}}{\text{Molar mass of Cu}}=\frac{89\times 10^{-3}g}{63.5g/mol}=1.40\times 10^{-3}mole$

Now we have to calculate the number of moles of $CuSO_4$

Number of moles of Cu = Number of moles of $CuSO_4$

Number of moles of $CuSO_4$ = $1.40\times 10^{-3}mole$

Now we have to calculate the molarity of $CuSO_4$

$\text{Molarity}=\frac{\text{Moles of }CuSO_4\times 1000}{\text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{1.40\times 10^{-3}mole\times 1000}{400.mL}=0.0035M$

To change mol/L into g/L, we need to multiply it with molar mass of $CuSO_4$

Molar mass of $CuSO_4$ = 159.609 g/mL

Concentration in g/L = $0.0035M\times 159.609g/mol=0.5586g/L\approx 5.6\times 10^{-1}g/L$

Thus, the original concentration of copper (II) sulfate in the sample is, $5.6\times 10^{-1}g/L$

3 0

3 years ago

An atom of a particular element has a volume of 7.8x10^-31 m^3. What is this volume in cubic nanometers

attashe74 [19]

Answer:

7.8 × 10∧-4 nm³

Explanation:

Given data:

volume = 7.8x10^-31 m^3

volume in nm³= ?

Solution:

I m³ = 1 × 10∧27

7.8 x 10^-31 × 1 × 10∧27 = 7.8 × 10∧-4 nm³

3 0

3 years ago

Can geothermal energy be used for electricity

saw5 [17]

Yea but its not used very often

3 0

4 years ago

PLEASE HELP WILL GIVE 20PTS AND WILL MARK BRAINLIEST FOR RIGHT ANSWER!!!

Marysya12 [62]

Answer:

C) 0.457

Explanation:

The ratio between O2 and H2O is 1:2 according to the balanced equation. You can find how many moles is O2 by : 5.12/22.4 = 0.22857 ( 1 mole = 22.4 litters)

Moles of H2O will be 0.22857 * 2 = 0.457142.

Therefore answer C)

7 0

3 years ago