Used an app called Mephyso to do the calculation.
. A 2.0-m wire carries a current of 15 A directed along the positive x axis in a region where the magnetic field is uniform and
1 answer:
Answer:
The resulting magnetic force on the wire is -1.2kN
Explanation:
The magnetic force on a current carrying wire of length 'L' with current 'I' in a magnetic field B is
F = I (L*B)
Finding (L * B) , where L = (2, 0, 0)m , B = (30, -40, 0)
L x B = = (0, 0, -80)
we can now solve
F = I (L x B) = I (-80)
F = -1200 kmN
F = -1200 kN * 10⁻³
F = -1.2kN
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Answer:
Explanation:
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The friction force on this case is defined as :
Where N represent the normal force, the kinetic friction coeffient and a the acceleration.
For this case we can assume that the only force is the friction force and we have:
Replacing the friction force we got:
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Assuming the final velocity is 0 we can find the distance like this: