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bezimeni [28]
1 year ago
12

in which of the following collisions would you expect the kinetic energy to be conserved? a. a bullet passes through a block of

wood. b. two bull elk charge each other and lock horns. c. two asteroids collide by a glancing blow, but do not actually hit each other, their only interaction being through gravity. d. two cars with springlike bumpers collide at fairly low speeds.
Physics
1 answer:
Scorpion4ik [409]1 year ago
8 0

An elastic collision is one in which the system does not experience a net loss of kinetic energy as a result of the collision. In elastic collisions, momentum and kinetic energy are both conserved.

<h3>Explain about the Elastic Collision?</h3>

A collision between two bodies in physics is referred to as an elastic collision if their combined kinetic energy stays constant. There is no net conversion of kinetic energy into other forms, such as heat, noise, or potential energy, in an ideal, fully elastic collision

An example of an elastic collision is when two balls collide at a pool table. It is an elastic collision when you throw a ball on the ground and it bounces back into your hand because there is no net change in the kinetic energy.

If there is no kinetic energy lost in the impact, the collision is said to be perfectly elastic. A collision is considered to be inelastic if any of the kinetic energy is converted to another kind of energy during the collision.

To learn more about Elastic Collision refer to:

brainly.com/question/7694106

#SPJ4

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kifflom [539]

Answer:

B can take 0.64 sec for the longest nap .

Explanation:

Given that,

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Distance = 30 m

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We need to calculate the time for A

Using equation of motion

s=ut+\dfrac{1}{2}at_{A}^2

Put the value in the equation

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t_{A}=\sqrt{\dfrac{30\times2}{1.6}}

t_{A}=6.12\ sec

We need to calculate the time for B

Using equation of motion

s=ut+\dfrac{1}{2}at_{B}^2

Put the value in the equation

30=0+\dfrac{1}{2}\times2.0\times t_{B}^2

t_{B}=\sqrt{\dfrac{30\times2}{2.0}}

t_{B}=5.48\ sec

We need to calculate the time for longest nap

Using formula for difference of time

t'=t_{A}-t_{B}

t'=6.12-5.48

t'=0.64\ s

Hence, B can take 0.64 sec for the longest nap .

4 0
4 years ago
A box, compressing a spring by 4 m, is loaded and ready. Moments later the 8.0 kg box has been launched with
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Answer:

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3 0
3 years ago
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