40 000 kg.m/s...P=MV then 20 000=M2V therefore Pnew=2MV i.e Pnew= 2Pold ...Pnew=2Pold...Pnew=2(20 000)...Pnew=40 000
Answer:
If the temperature of the colder object rises by the same amount as the temperature of the hotter object drops, then <u>the specific heats of both objects will be equal.</u>
Explanation:
If the temperature of the colder object rises by the same amount as the temperature of the hotter object drops when the two<u> objects of same mass</u> are brought into contact, then their specific heat capacity is equal.
<u>We can prove this by the equation of heat for the two bodies:</u>
<em>According to given condition,</em>
<em>when there is no heat loss from the system of two bodies then </em>
- Thermal conductivity is ultimately affects the rate of heat transfer, however the bodies will attain their final temperature based upon their mass and their specific heat capacities.
The temperature of the colder object will rise twice as much as the temperature of the hotter object only in two cases:
- when the specific heat of the colder object is half the specific heat of the hotter object while mass is equal for both.
OR
- the mass of colder object is half the mass of the hotter object while their specific heat is same.
Answer:
t = Δa / v
Explanation:
To know which option is not true, we shall fine a relationship between acceleration (a), velocity (v), time (t) and radius (r). This is illustrated below:
Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as shown below:
Acceleration = change in velocity / time
a = Δv / t ..... (1)
But
Δv = v₂ – v₁
Substitute the value of Δv into equation (1)
a = Δv / t
a = v₂ – v₁ / t ....... (2)
From equation (1), make Δv the subject of the equation.
a = Δv / t
Cross multiply
Δv = at .... (3)
From equation (1), make t the subject of the equation.
a = Δv / t
Cross multiply
at = Δv
Divide both side by a
t = Δv /a ...... (4)
From circular motion, centripetal's force is given by:
F = mv²/r
F = ma꜀
Therefore,
ma꜀ = mv²/r
Cancel out m
a꜀ = v²/r
SUMMARY:
a = Δv / t
a = v₂ – v₁ / t
Δv = at
t = Δv /a
a꜀ = v²/r
Considering the options given in question above, t = Δa / v is not a true statement.
Answer:
Nuestro mejor amigo escuchará la música más rápido a una temperatura de 36 ºC (309.15 K)
Explanation:
Supongase que el aire se comporta como un gas ideal y que experimenta un proceso adiabático, entonces la velocidad del sonido (
), medida en metros por segundo, queda traducida en la siguiente fórmula:
(1)
Donde:
- Coeficiente de dilatación térmica, sin unidad.
- Coeficiente universal de los gases ideales, medido en kilogramo-metros cuadrados por mol-Kelvin-segundo cuadrado.
- Temperatura, medida en Kelvin.
- Masa molar, medida en kilogramos por mol.
Como se puede ver, la velocidad del sonido es directamente proporcional a la raíz cuadrada de la temperatura. Por tanto, nuestro mejor amigo escuchará la música más rápido a una temperatura de 36 ºC (309.15 K)
Answer:
“Measurement” is the act of determining a target's size, length, weight, capacity, or other aspect. There are a number of terms similar to “measure” but which vary according to the purpose (such as “weight,” “calculate,” and “quantify.”) In general, measurement can be understood as one action within the term “instrumentation.”
Explanation:
• To show measured results using values and symbols. • To use measurement tools.
Measuring a target can be done through either direct measurement or indirect measurement. An Indirect measurement is done, for example, by using a dial gauge to measure the height difference between a measurement target and a gauge block and using that height to indirectly determine the target's height. Because this type of measurement is based on a reference, indirect measurement is also referred to as “comparative measurement.
An ”Direct measurement is measurement done by bringing the target into contact with the measurement system to read the length, height, or other aspect directly. Although direct measurement allows measurement results to be known as they are, errors may occur depending on the skill of the person doing the measurement.
