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3 years ago

What does the force diagram look like for a book at rest on a desk?

1 answer:

7 0

An arrow representing the weight of the book acts downwards on the table. An arrow of equal magnitude, but opposite direction represents the normal reaction force of the table on the book.

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The cannon on a battleship can fire a shell a maximum distance of 36.0 km.

Paraphin [41]

(a)The initial velocity of the shell will be 594.27 m/sec

(b)The maximum height it reaches will be 9000 m.

c)101.249 m meters lower will its surface be 36.0 km from the ship along a horizontal line parallel to the surface of the ship.

d)The error could be significant compared to the size of a target. Option C is correct.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

m is the mass of the block = Kg.

u is the initial velocity of fall = m/sec

h is the distance of fall = m

g is the acceleration of free fall = m/sec²

v is the hitting velocity of =?

The range of the projectile is;

$\rm R = \frac{u^2 sin 2 \theta }{g} \\\\ 36 \times 10^ 3 = \frac{U^2 sin 45^0}{9.81} \\\\ U= 594.27 \ m/sec$

The maximum height of the projectile is;

$\rm H = \frac{u^2 sin 2 \theta }{2g} \\\\ H = \frac{(594.27)^2\times (sin 45)^2}{2 \times 9.81 } \\\\ H = 9000 \ m$

The distance between its surface and the ship, measured in a horizontal arc parallel to the surface, will be 36.0 kilometers. The distance from the lower surface is found as;

$\rm( R_e + h)^2 = R_e^2+(36)^2 \\\\ (R_e)^2 = h^2+2R_e h= R_e^2 + 12196 \\\\ h^2 + 12800 h - 1296 = 0 \\\\ h = 101.249 \ m$

An error is a mistaken or erroneous action. In some contexts, an error is interchangeable with a mistake.

The difference between the calculated value and the original value is known as the error. The inaccuracy may be large in comparison to the target's size. Option C is correct.

Hence the initial velocity of the shell, maximum height, and the distance from the lower surface will be 594.27 m/sec,9000 m, and 101.249 m and option c for question d are correct respectively.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

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4 0

2 years ago

A car travels up a hill at a constant speed of 22 km/h and returns down the hill at a constant speed of 55 km/h. calculate the a

Ket [755]

The answer choice is 2.5

6 0

3 years ago

A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm un

8_murik_8 [283]

Answer:

The spring constant is 60,000 N

The total work done on it during the compression is 3 J

Explanation:

Given;

weight of the girl, W = 600 N

compression of the spring, x = 1 cm = 0.01 m

To determine the spring constant, we apply hook's law;

F = kx

where;

F is applied force or weight on the spring

k is the spring constant

x is the compression of the spring

k = F / x

k = 600 / 0.01

k = 60,000 N

The total work done on the spring = elastic potential energy of the spring, U;

U = ¹/₂kx²

U = ¹/₂(60000)(0.01)²

U = 3 J

Thus, the total work done on it during the compression is 3 J

3 0

3 years ago

A force of 20 N acts on a smaller piston of a hydraulic press with an area of 10 dm2. How much force does the liquid act on a

ivann1987 [24]

Answer:

166.67 N

Explanation:

Applying Pascal's principle,

Presure in the smaller piston(P') = Pressure in the bigger piston(P)

But,

Pressure = Force/Area

Pressure in the smaller piston(P') = Force applied to the smaller piston(F')/Area of the smaller piston(A')

Pressure in the bigger piston(P) = Force applied to the bigger piston(F)/Area of the bigger piston(A)

F'/A' = F/A.................. Equation 1

Make F the subject of the equation

F = F'A/A'.............. Equation 2

From the question,

Given: F' = 20 N, A = 120 cm², A' = 10 dm² = (10×100) = 1000 cm²

Substitute these values into equation 2

F = 20(1000)/120

F = 166.67 N

3 0

3 years ago

A proton and an electron are fixed in space with a separation of 859 nm. Calculate the electric potential at the midpoint betwee

makkiz [27]

Answer:

The electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts

Explanation:

Electric potential is given as;

V = E*r

where;

E is the electric field strength, = kq/r²

V = ( kq/r²)*r

V = kq/r

k is coulomb's constant = 8.99 X 10⁹ Nm²/C²

q is the charge of the particles = 1.6 X 10⁻¹⁹ C

r is the distance between the particles = 859 nm

At midpoint, the distance = r/2 = 859nm/2 = 429.5 nm

V = (8.99 X 10⁹ * 1.6 X 10⁻¹⁹)/ (429.5 X 10⁻⁹)

V = 3.349 X 10⁻³ Volts

Therefore, the electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts

3 0

3 years ago