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1 year ago

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which of the following astronomers introduced the most widely accepted hypothesis regarding the origin of the solar system?

1 answer:

Oksanka [162]1 year ago

6 0

The astronomers introduced the most widely accepted hypothesis regarding the origin of the solar system is Immanuel Kant in 1755.

Newton's equations of gravity and rotatory motion served as the foundation for most of Kant's theories. He believed that primaeval matter, which he believed to have been generated supernaturally, was dispersed throughout the cosmos. Small, chilly, hard particles made up this substance.

Due to the gravitational pull of one another, these particles were drawn to one another.

In his 1755 "The Universal Natural History and Views of the Heavens," Kant discusses astronomy as well as two significant cosmological theories. The first is his "Nebular Hypothesis" on the formation of stars and planets, in which he proposed that faint, thin clouds of dust and gas far out in space would collapse in on themselves under the influence of gravity, forcing them to spin to form a disc. The development of stars and planets from this rotating disc would account for the rotation of Earth and the other planets.

To learn more about Nebular Hypothesis refer the link:

brainly.com/question/27986174

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An object moves at 60 m/s in the +x direction. As it passes through the origin it gets a 4.5 m/s^2 acceleration in the -x direct

Brut [27]

Answer:

a) After 26.67 seconds it returns back to the origin

b) Velocity when it returns to the origin = 60 m/s in the -x direction

Explanation:

a) Let the starting position be origin and time be t.

After time t displacement, s = 0 m

Initial velocity, u = 60 m/s

Acceleration, a = -4.5 m/s²

We have equation of motion s = ut + 0.5 at²

Substituting

s = ut + 0.5 at²

0 = 60 x t + 0.5 x (-4.5) x t²

2.25t² - 60 t = 0

t² - 26.67 t = 0

t (t-26.67) = 0

t = 0s or t = 26.67 s

So after 26.67 seconds it returns back to the origin

b) We have equation of motion v = u + at

Initial velocity, u = 60 m/s

Acceleration, a = -4.5 m/s²

Time , t = 26.67

Substituting

v = 60 - 4.5 x 26.67 = -60 m/s

Velocity when it returns to the origin = 60 m/s in the -x direction

4 0

3 years ago

A charge of 1.0 × 10-6 μC is located inside a sphere, 1.25 cm from its center. What is the electric flux through the sphere due

Korvikt [17]

Answer:

$\Phi_E=0.11\frac{N\cdot m^2}{C}$

Explanation:

According to Gauss's Law, the electric flux of a charged sphere is the electric field multiplied by the area of the spherical surface:

$\Phi_E=EA\\\Phi_E=E(4\pi R^2)\\\Phi_E=\frac{q}{4\pi \epsilon_0 R^2}(4\pi R^2)\\\Phi_E=\frac{q}{\epsilon_0}$

This is identical to the electric flux of a point charge located in the center of the sphere.

$\Phi_E=\frac{1*10^{-12}C}{8.85*10^{-12} \frac{C^2}{N\cdot m^2}}\\\Phi_E=0.11\frac{N\cdot m^2}{C}$

8 0

3 years ago

How much power does a toaster have if it does 21,000 joules of work in 30 seconds?

marysya [2.9K]

Power = (work done) / (time to do the work)

   = (21,000 Joules) / (30 seconds)

   = (21,000 / 30) joule/sec

   =    700 watts

5 0

3 years ago

If Joe rides his bike for 15 minutes at 20 km/hour south, how far has he ridden? (Give the answer in km) Watch the units!

Virty [35]

Answer:

Distance covered by Joe, d = 5 km

Explanation:

It is given that,

Speed of Joe, v = 20 km/hour

Time taken by Joe, t = 15 minutes = 0.25 h

We need to find the distance he is covering. It can be calculated using definition of speed as :

$v=\dfrac{d}{t}$

$d=v\times t$

$d=20\times 0.25$

d = 5 km

So, Joe covers a distance of 5 km. Hence, this is the required solution.

3 0

3 years ago

Which of the following was NOT a main trade zone of the Indian Ocean Basin?

ycow [4]

C African zone is correct

6 0

3 years ago